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Ahat [919]
3 years ago
14

Which hypothesis was Louis Pasteur trying to confirm through his work?

Biology
1 answer:
tester [92]3 years ago
6 0
Answer:

B New cells come from preexisting cells.
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What is one advantage of clean-cutting
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Increased Water Flow

Explanation:

Supporters of clear-cutting contend that the practice results in increased soil water and stream flow, since when trees are removed from an area, the amount of water in that area increases.

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39:29
Ilya [14]

Answer:a

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Match the organ to the number showing the order of blood flow in the circulatory system.
trasher [3.6K]

Answer:

What sends oxygenated blood back to the heart from the lungs?

Oxygen-rich blood flows from the lungs back into the left atrium (LA), or the left upper chamber of the heart, through four pulmonary veins. Oxygen-rich blood then flows through the mitral valve (MV) into the left ventricle (LV), or the left lower chamber.

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Which is true of animals, but not of plants?
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Read 2 more answers
Two linked genes, A and B, are separated by 18 cM. A man with genotype AB/ab marries a woman who is ab/ab. The man’s father was
kolbaska11 [484]

Answer:

a) 9%.  

b) 16.8%.

Explanation:

a).

We are provided with the information that Two linked genes, A and B, are separated by 18 cM (centiMorgan). i.e the recombinant frequency is 18%

Also , the man's genotype is AB/ab... This only result to one explanation, that The man will definitely produce 18% of recombinant gametes which entails

9% Ab & 9% aB

i.e 0.09 Ab & 0.09 aB

On the other-hand, The mother ab/ab have tendency to produce just one single type of gamete which is ab

∴

The probability that their first child will be Ab/ab will be

Pr ( Ab/ab) = (0.09) x (1)

= 0.09

= 9%.  

b).

If the father produces 18% of recombinant gametes which entails

9% Ab & 9% aB , this typically implies that the number of the non-recombinant gametes will be;

100%-18% = 82%  ( non-recombinant gametes)

i.e genotype AB/ab = 82%

AB =41%; ab = 41%

AB = 0.41 ; ab = 0.41

Now, the probability that their first two children will both be ab/ab:

Using Multiplication Rule to calculate the probability that their first two children (ab/ab); we have:

 (0.41)(1) ×(0.41)(1)

= 0.1681

= 16.8%.

5 0
4 years ago
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