The product of two even numbers is even.
Let m and n be any integers so that 2m and 2k are two even numbers.
The product is 2m(2k) = 2(2mk), which is even.
Things to think about:
Why didn’t I just show you by using any two even numbers like the number 4 and the number 26?
Why did I change from "m" to "k" ? Are they really different numbers or could they be the same?
Why did I specifically say that m and k were integers?
The product of two odd numbers is an odd number.
Let m and k be any integers. This means that 2m+1 and 2k+1 are odd numbers.
The product is 4mk + 2m + 2k + 1 (hint: I used FOIL) which can be written as
2 ( 2mk + m + k ) + 1 which is an odd number.
Answer: B. 233 (rounded)
Step-by-step explanation:
1: 700/6= 166.6
2: 166.6+166.6=233.332
3 round to 233
Answer:
No
Step-by-step explanation:
Each ratio is irreducible, and they are different. Hence they are not the same value, so cannot be a proportion. A proportion is two equal ratios.
5 : 3 = 40 : 24
13 : 8 = 39 : 24 . . . . not the same as 40 : 24
_____
<em>Examples of proportions</em>
5/3 = 40/24 . . . is a proportion
13/8 = 39/24 . . . is a proportion
Answer: z < 4
z+4 > 2z
z+4-z > 2z-z ..... Subtract z from both sides
4 > z
z < 4
So the solution set for z is any number that is less than 4, which could be something like z = 2 or z = 3.
