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Valentin [98]
3 years ago
15

Brainliest and Five Stars for correct answers

Mathematics
1 answer:
wel3 years ago
3 0
\bf \lim\limits_{x\to 9}~\cfrac{x^2-81}{x-9}\implies \cfrac{\stackrel{\textit{difference of squares}}{x^2-9^2}}{x-9}\implies \cfrac{\underline{(x-9)}(x+9)}{\underline{(x-9)}}
\\\\\\
\lim\limits_{x\to 9}~x+9\implies (9)+9\implies 18
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The answer to your question is below

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I think your functions are wrong they must be       f(x) = 1/2x    f⁻¹(x) = 2x        

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