Brainliest and Five Stars for correct answers

1 answer:

wel3 years ago

3 0

$\bf \lim\limits_{x\to 9}~\cfrac{x^2-81}{x-9}\implies \cfrac{\stackrel{\textit{difference of squares}}{x^2-9^2}}{x-9}\implies \cfrac{\underline{(x-9)}(x+9)}{\underline{(x-9)}}
\\\\\\
\lim\limits_{x\to 9}~x+9\implies (9)+9\implies 18$

You might be interested in

A wall that is 10 feet high and 20 feet long contains one ton of bricks. How many tons should be purchased to brick a wall that

vitfil [10]

Answer:

9 tons

Step-by-step explanation:

So first we have to figure out the area of the smaller wall. We know it is 10 feet high and 20 feet long, so we multiply the length and width together to get 200 square feet, and that equals 1 ton. Now if we take the 1800 square foot wall and divide it by the smaller wall, we get 9. This is because the larger wall is 9 times the size of the smaller wall. So if the smaller wall needs 1 ton, and the larger would need 9 times the amount, we would need 9 tons.

7 0

4 years ago

Read 2 more answers

PLEASE HELP ASAP, THANK YOU

nlexa [21]

First step is to plot all the given coordinates in the xy plane.

Notice that after plotting the points A, B, C and D, we have got the figure ABCD is a trapezium with bases AD = 4 units, BC = 6 units and height: DE= 5 units.

Formula to find the area of trapezium is:

Area = $\frac{(AD+BC)}{2} *DE$