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Valentin [98]
3 years ago
15

Brainliest and Five Stars for correct answers

Mathematics
1 answer:
wel3 years ago
3 0
\bf \lim\limits_{x\to 9}~\cfrac{x^2-81}{x-9}\implies \cfrac{\stackrel{\textit{difference of squares}}{x^2-9^2}}{x-9}\implies \cfrac{\underline{(x-9)}(x+9)}{\underline{(x-9)}}
\\\\\\
\lim\limits_{x\to 9}~x+9\implies (9)+9\implies 18
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Please help me I’ll give you brainless it’s due in 20 minutes
ankoles [38]

Answer:

*In Explanation

Step-by-step explanation:

<u>1) Start by just substituting the value of x (given in equation 1) into the second equation:</u>

y = 3x - 1

y = 3(2) - 1

y = 6-1 = 5

<u>2) Since both equations have x on one side, make both equations equal to one another:</u>

2y + 4 = 9 - 3y

<u>Solve for y:</u>

5y = 5

y = 1

<u>Plug y = 1 into either one of the given equations and solve for x:</u>

I'll use first equation:

x = 2y + 4

x = 2(1) + 4

x = 6

<u>3) When substituting X into the second equation, remember to use parenthesis:</u>

The student was substituting x from equation 1 into equation 2, but they forgot to multiply ALL of 2y + 3 by 2.

x = 2y + 3

Substitute into 2nd eqn:

y = 2(2y + 3) - 9

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3 years ago
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Answer:

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Step-by-step explanation:

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Cloud [144]

Answer:

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Step-by-step explanation:

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Pls only do this if yk it because i’m giving correct answer brainliest! :))
Leno4ka [110]

Answer:

x=2+\frac{1}{2}\sqrt[]{21}

or

x=2-\frac{1}{2}\sqrt{{21}

Step-by-step explanation:

4x^2-16x-26=-21

Add 21 on both sides.

4x^2-16x-26+21=-21+21

4x^2-16x-5=0

a=4

b=-16

c=-5

x=\frac{-b\frac{+}{}\sqrt[]{b^2-4ac}  }{2a}

x=\frac{-(-16)\frac{+}{}\sqrt[]{(-16)^2-4(4)(-5)}  }{2(4)}

x=\frac{16\frac{+}{}\sqrt[]{256+80}  }{8}

x=\frac{16\frac{+}{}\sqrt[]{336}  }{8}

x=\frac{16\frac{+}{}\sqrt[]{2^2*2^2*21}  }{8}

x=\frac{16\frac{+}{}2*2\sqrt[]{21}  }{8}

x=\frac{16\frac{+}{}4\sqrt[]{21}  }{8}

---------------------------------------------------------------------------

x=\frac{16}{8}+\frac{4\sqrt[]{21}}{8}

x=2+\frac{1}{2}\sqrt[]{21}

---------------------------------------------------------------------------

x=\frac{16}{8}-\frac{4\sqrt[]{21}}{8}\\x=2-\frac{1}{2}\sqrt{{21}

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The answer is two :))))
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