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spayn [35]
3 years ago
6

OUCH MY BRAIN IS HURTING AFTER TRYING TO SOLVE THIS QUESTION

Mathematics
1 answer:
maria [59]3 years ago
4 0
300° CCW is the same as 60° CW. N will show up where H is now.

The 3rd selection is appropriate.
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amanda increased the amount of protein she eats evry day from 48 to 54 g by what percentage di amanda increas3 the amount of pro
sammy [17]

Answer:

the amount increased by approximatley 12%

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Pre-Calc: Find all the zeros of the function.
uysha [10]

The zeros of the polynomial function are y = 4/5, y = -4/5 and y = ±4/5√i and the polynomial as a product of the linear factors is f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

<h3>What are polynomial expressions?</h3>

Polynomial expressions are mathematical statements that are represented by variables, coefficients and operators

<h3>How to determine the zeros of the polynomial?</h3>

The polynomial equation is given as

f(y) = 625y^4 - 256

Express the terms as an exponent of 4

So, we have

f(y) = (5y)^4 - 4^4

Express the terms as an exponent of 2

So, we have

f(y) = (25y^2)^2 - 16^2

Apply the difference of two squares

So, we have

f(y) = (25y^2 - 16)(25y^2 + 16)

Apply the difference of two squares

So, we have

f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

Set the equation to 0

So, we have

(5y - 4)(5y + 4)(25y^2 + 16) = 0

Expand the equation

So, we have

5y - 4 = 0, 5y + 4 = 0 and 25y^2 + 16 = 0

This gives

5y = 4, 5y = -4 and 25y^2 = -16

Solve the factors of the equation

So, we have

y = 4/5, y = -4/5 and y = ±4/5√i

Hence, the zeros of the polynomial function are y = 4/5, y = -4/5 and y = ±4/5√i

How to write the polynomial as a product of the linear factors?

In (a), we have

The polynomial equation is given as

f(y) = 625y^4 - 256

Express the terms as an exponent of 4

So, we have

f(y) = (5y)^4 - 4^4

Express the terms as an exponent of 2

So, we have

f(y) = (25y^2)^2 - 16^2

Apply the difference of two squares

So, we have

f(y) = (25y^2 - 16)(25y^2 + 16)

Apply the difference of two squares

So, we have

f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

Hence, the polynomial as a product of the linear factors is f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

Read more about polynomial at

brainly.com/question/17517586

#SPJ1

5 0
1 year ago
HEY YOU!! PLEASE I NEED HELPPP<br><br> find angle BAC and angle FAB
serious [3.7K]

Answer:

m∠BAC = 105°

m∠FAB = 75°

Step-by-step explanation:

By using the property of an exterior angle of a triangle,

Measure of an exterior angle is equal to the sum of opposite two angles of a triangle.

From the triangle given in the picture,

m∠ABC + m∠BCA + m∠CAB = 180°

(13x - 3)° = (3x + 2)° + 55°

13x - 3 = 3x + 57

13x - 3x = 57 + 3

10x = 60

x = 6

m∠FAB = (13x - 3)° = 75°

m∠ABC = (3x + 2)° = 20°

Since, ∠BAC and ∠FAB are the linear pair of angles,

m∠BAC + m∠FAB = 180°

m∠BAC + 75° = 180°

m∠BAC = 180° - 75° = 105°

8 0
3 years ago
Which decimal number is equal to 4/9?
Ratling [72]
4\9=.444444444
answer=choice D
6 0
3 years ago
Read 2 more answers
Carly buys t play tickets at $14.50 per ticket and t choir concert tickets at $5.50 per ticket. What is the cost for play ticket
Step2247 [10]

Answer:

20t

Step-by-step explanation:

Carly buys t play tickets at $14.50 per ticket and t choir concert tickets at $5.50 per ticket. What is the cost for play tickets and choir concert tickets.

The cost of the play tickets is the number of play tickets multiplied by the cost of each ticket.

Play tickets: number of tickets: t; cost of each ticket: $14.50

Cost of play tickets: 14.50t

The cost of the choir tickets is the number of choir tickets multiplied by the cost of each ticket.

Choir tickets: number of tickets: t; cost of each ticket: $5.50

Cost of choir tickets: 5.50t

Total cost of play tickets and choir tickets:

14.50t + 5.50t = 20t

4 0
2 years ago
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