Answer:
1/16
Step-by-step explanation:
f(x) = 2^x
Let x = -4
f(-4) = 2 ^ -4
We know that a^-b = 1/a^b
= 1/2^4
= 1/16
Answer:
a. dy/dx = -2/3
b. dy/dx = -28
Step-by-step explanation:
One way to do this is to assume that x and y are functions of something else, say "t", then differentiate with respect to that. If we write dx/dt = x' and dy/dt = y', then the required derivative is y'/x' = dy/dx.
a. x'·y^3 +x·(3y^2·y') = 0
y'/x' = -y^3/(3xy^2) = -y/(3x)
For the given point, this is ...
dy/dx = -2/3
___
b. 2x·x' +x^2·y' -2x'·y^3 -2x·(3y^2·y') + 0 = 2x' + 2y'
y'(x^2 -6xy^2 -2) = x'(2 -2x +2y^3)
y'/x' = 2(1 -x +y^3)/(x^2 +6xy^2 -2)
For the given point, this is ...
dy/dx = 2(1 -0 +27)/(0 +0 -2)
dy/dx = -28
_____
The attached graphs show these to be plausible values for the derivatives at the given points.
Answer:
i think it is D
Step-by-step explanation:
i hope this helped!
p.s it would be cool if you gave me brainliest.
Answer:
Cost of a coffee is <u>$2.5</u> and cost of a latte is <u>$4.25.</u>
Step-by-step explanation:
Let cost of 1 coffee be 'c' and cost of 1 latte be 'l' dollars.
Given:
4 coffees and 12 lattes cost $61.
12 coffees and 7 lattes cost $59.75.
∵ 1 coffee cost = 
∴ 4 coffees cost =
and 12 coffee cost = 
∵ 1 latte cost = 
∴ 12 lattes cost =
and 7 lattes cost = 
Now, as per question:

Now, multiplying equation (1) by -3 and adding the result to equation (2). This gives,

Now, plug in the value of 'l' in equation 1 to solve for 'c'. This gives,

Therefore, cost of a coffee is $2.5 and cost of a latte is $4.25.