Answer: the eastbound train had travelled 12 miles
Explanation: using Pythagoras theorem, we know that
X^2 = a^2 + b^2
Where ^ stands for raised to power.
Let
a stand for the train going towards North and
b stands for the train going towards east.
X stands for the total distance between train a and b = 20 miles.
By Pythagoras rule
X^2 = a^2 + b^2
20^2 = 16^2 + b^2
400 = 256 + b^2 so that
b^2 = 400 - 256 = 144
b = √144
b = 12 miles.
The correct answer is the third option.
Answer:
y = 11
Step-by-step explanation:
Since our plane is parallel to the xz plane, the x and z are independent of each other, i.e. they could be anything. So xz plane has an equation of y = 0. So if this plane is located 11 units to the right of the xz plane then its equation must be y = 11.
Answer:
Step-by-step explanation:
Both cars, X and Y travelled 80 miles each.
Speed = distance/time
If car X took 2 hours to travel 80 miles, it means that the speed at which car X travelled is
80/2 = 40 mph
If car Y traveled at an average speed that was 50 percent faster than the average speed of car X, it means that the speed at which car X travelled is
40 + 0.5 × 40 = 60 mph
Time = distance/speed
Therefore, time taken by car Y to travel 80 miles is
80/60 = 1.33 hours
X² + x - 12 / x² - x - 20 ÷ 3x² - 24x + 45 / 12x² - 48x - 60
x² + x - 12 / x² - x - 20 * 12x² - 48x - 60 / 3x² - 24x + 45
<u>(x² + x - 12)(12x² - 48x - 60)</u>
(x² - x - 20)(3x² - 24x + 45)
<span><u>12x^4 - 48x³ - 60x² + 12x³ - 48x² - 60x - 144x² + 576x + 720</u>
</span>3x^4 - 24x³ + 45x² - 3x³ + 24x² - 45x - 60x² + 480x - 900
<span>
<u>12x^4 - 48x³ + 12x³ - 60x² - 48x² - 144x² - 60x + 576x + 720</u></span>
3x^4 - 24x³ - 3x³ + 45x² + 24x² - 60x² - 45x + 480x - 900
<u>12x^4 - 36x³ - 252x² + 516x + 720</u>
3x^4 - 27x³ + 9x² + 435x - 900
<u>12(x^4 - 3x³ - 21x² + 43x + 60) </u>
3(x^4 - 9x³ + 3x² + 145x + 300)
<u>4(</u><span><u>x^4 - 3x³ - 21x² + 43x + 60) </u>
</span><span> (x^4 - 9x³ + 3x² + 145x + 300)</span>
