Answer:for ax^2+bx+c=0 the discriminant is b^2-4ac
there are 3 basic cases of what happens for different discriminants
1. if the discriminant is less than 0, then there are no real zeroes
2. if the discriminant is 0, then it has 1 zero
3. if the discriminant is greater than 0, it has 2 zeroes
so given
0=3x^2-7x+4
a=3,b=-7,c=4
thus the discriminant is (-7)^2-4(3)(4)=49-48=1
the discriminant is 1. 1 is positive, thus the equation has 2 zeroes because the discriminant is greater than 0
the answer is the equation has two zeroes because the discriminant is greater than 0
Step-by-step explanation:
Answer:
Please check the explanation.
Step-by-step explanation:
Given the function
We know that the domain of the function is the set of input or arguments for which the function is real and defined.
In other words,
- Domain refers to all the possible sets of input values on the x-axis.
Now, determine non-negative values for radicals so that we can sort out the domain values for which the function can be defined.
as x³ - 16x ≥ 0
Thus, identifying the intervals:
Thus,
The domain of the function f(x) is:
![x\left(x+4\right)\left(x-4\right)\ge \:0\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-4\le \:x\le \:0\quad \mathrm{or}\quad \:x\ge \:4\:\\ \:\mathrm{Interval\:Notation:}&\:\left[-4,\:0\right]\cup \:[4,\:\infty \:)\end{bmatrix}](https://tex.z-dn.net/?f=x%5Cleft%28x%2B4%5Cright%29%5Cleft%28x-4%5Cright%29%5Cge%20%5C%3A0%5Cquad%20%3A%5Cquad%20%5Cbegin%7Bbmatrix%7D%5Cmathrm%7BSolution%3A%7D%5C%3A%26%5C%3A-4%5Cle%20%5C%3Ax%5Cle%20%5C%3A0%5Cquad%20%5Cmathrm%7Bor%7D%5Cquad%20%5C%3Ax%5Cge%20%5C%3A4%5C%3A%5C%5C%20%5C%3A%5Cmathrm%7BInterval%5C%3ANotation%3A%7D%26%5C%3A%5Cleft%5B-4%2C%5C%3A0%5Cright%5D%5Ccup%20%5C%3A%5B4%2C%5C%3A%5Cinfty%20%5C%3A%29%5Cend%7Bbmatrix%7D)
And the Least Value of the domain is -4.
Answer:
LESS GO
Step-by-step explanation:
U DA BEST
Answer:
Step-by-step explanation:
If you call "5x-2x^2+1" an "equation," then you must equate 5x-2x^2+1 to 0:
5x-2x^2+1 = 0
This is a quadratic equation. Rearranging the terms in descending order by powers of x, we get:
-2x^2 + 5x + 1 = 0. Here the coefficients are a = -2, b = 5 and c = 1.
Use the quadratic formula to solve for x:
First find the discriminant, b^2 - 4ac: 25 - 4(-2)(1) = 25 + 8 = 33
Because the discriminant is positive, the roots of this quadratic are real and unequal.
-b ± √(discriminant)
Applying the quadratic formula x = --------------------------------
2a
we get:
-5 ± √33 -5 + √33
x = ----------------- = --------------------- and
2(-2) -4
-5 - √33
---------------
-4
-27 divided by 9 = -3, 4 x -6 = -24, 12 x -10 = -120, -45 divided by -5 = 9, 7 x -3 = -21, 72 divided by -8 = -9, 64 dibided by 8 is 8, and -8 x 6 is -48. good luck!! ^_^
