Answer:
x=1
Step-by-step explanation:
Answer:
in
Step-by-step explanation:
I don't know if you got this pic but this is the answer for this pic
Answer:
D) 12,656
Step-by-step explanation:
First of all, as they have given us 3 quantities of plants in 1/2 an acre, we can work out the average amount of plants in 1 whole acre.
In the first 1/2 acre there were:
In the second 1/2 acre there were:
In the third 1/2 acre there were:
to work out the average, we add all these together then divide them by 3 (as there are 3 examples)
291 + 327 + 286 = 904
904 ÷ 3 = 301.3 (this is the average amount of plants in every 1/2 acre.) If we multiply this answer by 2 we will get the average amount of plants in every acre.
301.3 x 2 = 602.67 (average plants in every 1 acre) multiply by total acres (21) for your answer
602.67 x 21 = 12656 average plants in total
I hope this was helpful :-)
Answer:
You would do $1.75 x 1,000. That would be 1$,750. Then, you would take away that $95 because they spent buying the box of tea bags, and their total would be $1,750 - $95 = $1,655.
Answer:
(0.5848 ; 0.6552)
We are confident that about 58% to 66% of sea foods in the country are Mislabelled.
No, criticism isnt valid and generalization can be made once the assumptions for constructing a confidence interval is met.
Step-by-step explanation:
Sample size, n = 51
p = 0.62
1 - p = 1 - 0.62 = 0.38
n = 515
Confidence level = 90% = Zcritical at 90% = 1.645
Confidence interval = (p ± margin of error)
Margin of Error = Zcritical * sqrt[(p(1-p))/n]
Margin of Error = 1.645 * sqrt[(0.62(0.38))/515]
Margin of Error = 1.645 * 0.0214
Margin of Error = 0.035203
Lower boundary = (0.62 - 0.035203) = 0.584797
Upper boundary = (0.62 + 0.035203) = 0.655203
(0.5848 ; 0.6552)
We are confident that about 58% to 66% of sea foods in the country are Mislabelled.
No, criticism isnt valid and generalization can be made once the assumptions for constructing a confidence interval is met.
