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dolphi86 [110]
3 years ago
8

What are the coordinates of the vertex of the function f(x) = x2 - 12x + 5?

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
6 0

Answer:

The vertex is the point (6,-31)

Step-by-step explanation:

we have

f(x)=x^2-12x+5

This is a vertical parabola open upward

The vertex represent a minimum

Convert to vertex form

Complete the square

f(x)=(x^2-12x+6^2)+5-6^2

f(x)=(x^2-12x+36)-31

Rewrite as perfect squares

f(x)=(x-6)^2-31 -----> equation in vertex form

therefore

The vertex is the point (6,-31)

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Mr. Hollins determines that he gives away $800 each month. If he gives away 16% of his budget, then how much is his overall budg
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Answer:

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Step-by-step explanation:

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1 year ago
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e-lub [12.9K]

Answer:

The equation in the standard form is

y+2x=5

Step-by-step explanation:

Given the points

  • (6, -7)
  • (4, -3)

Finding the slope between (6, -7) and (4, -3)

\left(x_1,\:y_1\right)=\left(6,\:-7\right),\:\left(x_2,\:y_2\right)=\left(4,\:-3\right)

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

m=\frac{-3-\left(-7\right)}{4-6}

m=-2

As the point-slope form is defined as

y-y_1=m\left(x-x_1\right)

substituting the values m = -2 and the point (6, -7)

y-y_1=m\left(x-x_1\right)

y-\left(-7\right)=-2\left(x-6\right)

Writing the equation in the standard form form

As we know that the equation in the standard form is

Ax+By=C

where x and y are variables and A, B and C are constants

converting the equation in standard form

y-\left(-7\right)=-2\left(x-6\right)

y+7=-2\left(x-6\right)

subtract 7 from both sides

y+7-7=-2\left(x-6\right)-7

y=-2x+5

y+2x=5

Therefore, the equation in the standard form is

y+2x=5

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Step-by-step explanation:

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