All categories

3 years ago

The Edwards family's bill for dinner is $52.95. How much should they tip their server? (Assuming the normal 15%)

Mathematics

2 answers:

Solnce55 [7]3 years ago

8 0

15% of 52.95 is 7.94

so they should tip $7.94

castortr0y [4]3 years ago

3 0

Answer

Find out the how much should they tip their server .

To prove

As given

The Edwards family's bill for dinner is $52.95.

The tip 15% .

15% is written in the decimal form.

$= \frac{15}{100}$

= 0.15

Tip paid by the Edwards family's = 0.15 × 52.95

= $7.94(Approx)

Therefore the tip paid by the Edwards family's is $7.94 .

You might be interested in

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

postnew [5]

I cannot help you with the first draging part since it needs to be done form your device.

But I can help you with the expression. Anything to the power of 0 power is equal to 1. Therefore:

$2^{0} = 1$

Hope it helped,

BioTeacher101

7 0

3 years ago

What is 300 divided by 400

Anna35 [415]

Answer:

0.75

Step-by-step explanation:

300 out of 400 is the same as 3/4.

3/4 converted to a decimal is 0.75.

8 0

3 years ago

Can someone pls help with this? i’ll give brainliest :)

raketka [301]

Answer:

D (I think)

Step-by-step explanation:

I used a right triangle calculator and that was the answer

Below is the process the calculator did, hope it helps.

$c = \sqrt{a^{2} +b^{2}$

$\sqrt{12^{2} + 9^{2} } = 15$

6 0

2 years ago

a daily newspaper has 10225 subscribers when it began publication. six years old later it has 8200 subscribers what is the avera

seraphim [82]

Answer:

The rate of change in number of subscriber for the six years is 3.62%

Step-by-step explanation:

Given as :

The initial subscriber of newspaper = p = 10225

The subscriber of newspaper after 6 years of publish = P = 8200

The time period = t = 6 years

Let The average yearly rate of change = r%

Now, According to question

The subscriber of newspaper after n years = initial subscriber × $(1-\dfrac{\textrm rate}{100})^{\textrm time}$

Or, P = p × $(1-\dfrac{\textrm r}{100})^{\textrm t}$

Or, 8200 = 10225 × $(1-\dfrac{\textrm r}{100})^{\textrm 6}$

Or, $\dfrac{8200}{10225}$ = $(1-\dfrac{\textrm r}{100})^{\textrm 6}$

Or, 0.80195 = $(1-\dfrac{\textrm r}{100})^{\textrm 6}$

Taking power $\dfrac{1}{6}$ both side

So, $(0.80195 )^{\frac{1}{6}}$ = $((1 - \frac{r}{100} )^{6})^{\frac{1}{6}}$

Or, 0.9638 = 1 - $\dfrac{r}{100}$

Or, $\dfrac{r}{100}$ = 1 - 0.9638

Or, $\dfrac{r}{100}$ = 0.0362

Or, r = 0.0362 × 100

i.e r = 3.62

So, The rate of change in subscriber = 3.62%

Hence, The rate of change in number of subscriber for the six years is 3.62% . Answer

4 0

3 years ago

Order these from least to greatest: |–15|, |4|, –|15|, |–5|

Alenkinab [10]

-/15/, /4/, /-5/,/ -15/

6 0

3 years ago

Read 2 more answers