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netineya [11]
3 years ago
14

If f(x) is a fifth degree polynomial, is it possible that it has exactly 5 complex roots?

Mathematics
1 answer:
Zolol [24]3 years ago
4 0

No.

A fifth degree polynomial, having a graph that increases and starts from below x-axis.

Therefore, no matter what equation it is. The fifth degree polynomial will intercept x-axis AT LEAST one.

The fifth degree polynomial can have only at maximum, 4 complex roots.

<em>You can try drawing or seeing the graph of fifth-degree polynomial function. No matter what equations, they still intercept at least one x-value.</em>

<em />

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Here you go -12.4 - 5.75 x is your Answer
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Solve the equation.<br> (x-5)(x+3)=0
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(x-5)(x+3)=0
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x(x+3) -5(x+3)
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he commercial division of a real estate firm is conducting a regression analysis of the relationship between , annual gross rent
blondinia [14]

Answer:

Number of apartment = 9

Step-by-step explanation:

Given the ANOVA result :

ANOVA ____ df ____ SS

Regression __ 1 ___ 41587.1

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4 0
3 years ago
Please help me now ! Thank you
jarptica [38.1K]
First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now

2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4

At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real. 

Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result. 

For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196

No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.

So x^2 = -4 has no real solutions. Taking the square root of both sides leads to

x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values


5 0
3 years ago
What is the constant of 2x+3y+6
vekshin1

Answer:

6

Step-by-step explanation:

Constants are any numbers that don't change.

2x + 3y + 6

Since "6" is the only number here, that is the only constant.

Best of Luck!

3 0
3 years ago
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