Answer:
120 = 2³ × 3 × 5
210 = 2 × 3 × 5 × 7
LCM(120 ; 210) = 2³ × 3 × 5 × 7 = 840
y = (9 / (x^2)) + 2
Rewrite in terms of f(x):
y = (9/(g(x))) + 2
To get
g(x) = x^2
f(x) = 9/x + 2
To find the cost of one slice 12.37/5= 2.47 per slice.
so y= 2.47p+1.12
We can solve this problem by referring to the standard
probability distribution tables for z.
We are required to find for the number of samples given the
proportion (P = 5% = 0.05) and confidence level of 95%. This would give a value
of z equivalent to:
z = 1.96
Since the problem states that it should be within the true
proportion then p = 0.5
Now we can find for the sample size using the formula:
n = (z^2) p q /E^2
where,
<span> p = 0.5</span>
q = 1 – p = 0.5
E = estimate of 5% = 0.05
Substituting:
n = (1.96^2) 0.5 * 0.5 / 0.05^2
n = 384.16
<span>Around 385students are required.</span>
