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mina [271]
3 years ago
11

The ideal temperature of a freezer to store a particular brand of ice cream is 0°F, with a fluctuation of no more than 2°F. Whic

h inequality represents this situation if t is the temperature of the freezer?
Mathematics
1 answer:
yan [13]3 years ago
8 0

Answer:

| x - 0 | ≤ 2

Step-by-step explanation:

Given,

The ideal temperature of the freezer = 0° F,

Also, it can fluctuate by 2° F,

Thus, if x represents the temperature of the freezer,

Then, there can be two cases,

Case 1 : x > 0,

⇒ x - 0 ≤ 2

Case 2 : If x < 0,

⇒ 0 - x ≤ 2,

⇒ -( x - 0 ) ≤ 2,

By combining the inequalities,

We get,

| x - 0 | ≤ 2,

Which is the required inequality.

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The first three steps of completing the square to solve the quadratic equation x2 +4x-6=0
hodyreva [135]

Answer:


Step-by-step explanation:

1.  Move the 6 to the other side:   x^2 +4x                        =6

2.  Square half the coefficient of the x term:  (4/2)^2 = 4

3.  Add this 4, and then subtract this 4, from x^2 + 4x:

     x^2 +4x + 4 - 4                       =6

4.  Rewrite this perfect square as the square of a binomial:

      (x + 2)^2   -   4   = 6

5.  Add 4 to both sides:    (x + 2)^2 =  10

6.  Find the sqrt of both sides:  x + 2 = √

8 0
3 years ago
The temperature was very cold.
ratelena [41]

Answer:

51-32+14=33

33÷3=11

answer is 11

3 0
2 years ago
Find two positive numbers whose product is 36 and whose sum is a minimum.
alukav5142 [94]
Let one of the numbers be x. The other number cab then be represented as 36-x (x+36-x = 36).
The product can then be represented as y = x(36-x) or y=36x-x2

The maximum or minimum is always on the axis of symmetry which has the formula x=-b/2a.
In our case, the axis of symmetry is -36/-2, so x=18.

If one number is 18 and the 2 numbers add to 36, the other number is 18 as well.
So the 2 numbers are 18 and 18 and the maximum product is 324,
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2 years ago
Classify the expression: −2x
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Answer:

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Step-by-step explanation:

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4 0
3 years ago
HELP
Sonbull [250]

Answer:

A. 121 ⇒ III. 11

B. 64 ⇒ II. 4 and IV. 8

C. 27 ⇒ I. 3

D. 125 ⇒ V. 5

E. 16 ⇒ II. 4

Step-by-step explanation:

Let us find the correct answer

∵ 121 = 11 × 11

∴ The square root 121 is 11

∴ A. 121 ⇒ III. 11

∵ 64 = 8 × 8

∴ The square root of 64 is 8

∵ 64 = 4 × 4 × 4

∴ The cube root of 64 is 4

∴ B. 64 ⇒ II. 4 and IV. 8

∵ 27 = 3 × 3 × 3

∴ The cube root of 27 is 3

∴ C. 27 ⇒ I. 3

∵ 125 = 5 × 5 × 5

∴ The cube root of 125 is 5

∴ D. 125 ⇒ V. 5

∵ 16 = 4 × 4

∴ The square root of 16 is 4

∴ E. 16 ⇒ II. 4

5 0
3 years ago
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