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mina [271]
3 years ago
11

The ideal temperature of a freezer to store a particular brand of ice cream is 0°F, with a fluctuation of no more than 2°F. Whic

h inequality represents this situation if t is the temperature of the freezer?
Mathematics
1 answer:
yan [13]3 years ago
8 0

Answer:

| x - 0 | ≤ 2

Step-by-step explanation:

Given,

The ideal temperature of the freezer = 0° F,

Also, it can fluctuate by 2° F,

Thus, if x represents the temperature of the freezer,

Then, there can be two cases,

Case 1 : x > 0,

⇒ x - 0 ≤ 2

Case 2 : If x < 0,

⇒ 0 - x ≤ 2,

⇒ -( x - 0 ) ≤ 2,

By combining the inequalities,

We get,

| x - 0 | ≤ 2,

Which is the required inequality.

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4000 - 500 = 3500
3 0
3 years ago
Find L when P= 24 and W = 6.<br> P = 2L+ 2W (perimeter of a rectangle)<br> L =
Anon25 [30]

Answer:

6

Step-by-step explanation:

24 = 2L + 2(6), multiply...

24 = 2L + 12, subtract 12 to both sides...

12 = 2L, divide 2 to both sides to isolate the varibale L

6 = L

Therefroe, L = 6

8 0
2 years ago
3. Segment GE is an angle bisector of both
777dan777 [17]

ΔHGE and ΔFGE are congruent by the Angle-Side-Angle Congruence Theorem (ASA).

<em><u>Recall:</u></em>

  • A segment that divides an angle into equal parts is known as an angle bisector.
  • Two triangles are congruent by the ASA Congruence Theorem if they share a common side and have two pairs of congruent angles.

In the diagram given, Angle bisector, GE, divides ∠HEF into congruent angles,  ∠HEG ≅ ∠GEF.

Also divides ∠FGH into congruent angles, ∠HGE ≅ ∠FGE.

Both triangles also share a common side, GE

<em>This implies that: ΔHGE and ΔFGE have:</em>

two pairs of congruent angles - ∠HEG ≅ ∠GEF and ∠HGE ≅ ∠FGE

a shared side - GE

Therefore, ΔHGE and ΔFGE are congruent by the Angle-Side-Angle Congruence Theorem (ASA).

Learn more about ASA Congruence Theorem on:

brainly.com/question/82493

4 0
2 years ago
Please solve my question ​
Rina8888 [55]

Answer:

u should redder the reader about the

formulas as it is a direct question

6 0
3 years ago
Read 2 more answers
In what situation might you have to calculate the surface area of volume of a solid?
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One application of volume is determining the density of an object. Assume the object is made of a pure element (eg: gold). If we know the volume (v) of the object, and we know the mass (m), then we can use the formula D = m/v to figure out the density D. Knowing the volume is also handy to determine if the object can fit into a larger space or not. Another application is figuring out how much water is needed to fill up the inner space of the 3D solid (assuming it's hollow on the inside).

The surface area is handy to figure out how much material is needed to cover the outer surface. This material can be paint, paper, metal sheets, or whatever you can think of really. A good example is wrapping a present and the assumption is that there is no overlap. 
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