The dimensions of the prism can be 2x, 2x+3 and x+6.
We first factor out the GCF of the trinomial. The GCF of the coefficients is 2. Each term has an x in common as well, so the GCF is 2x.
Factoring out the 2x, we have
2x(2x²+15x+18).
To factor the remaining trinomial, we find factors of 2*18=36 that sum to 15. 12*3 = 36 and 12+3 = 15. We split up 15x into 12x and 3x:
2x(2x²+12x+3x+18)
Now we group together the first two terms in parentheses and the last two:
2x((2x²+12x)+(3x+18))
Factor out the GCF of the first group:
2x(2x(x+6)+(3x+18))
Factor out the GCF of the second group:
2x(2x(x+6)+3(x+6))
Factoring out what these have in common,
2x(x+6)(2x+3)
The value of angle x is 113 degrees and y is 67 degrees.
What is angle?
In euclidean geometry, an angle is that the figure shaped by 2 rays, referred to as the perimeters of the angle, sharing a typical end point, referred to as the vertex of the angle. Angles shaped by 2 rays exist the plane that contains the rays.
Main body:
Given ;
∠C = 62°
∠A =51°
according to triangle sum property: Sum of angles of triangle is 180°
Using it,
62° +51° +∠y = 180°
113°+ ∠y =180°
∠y = 67°
∠x is equal to the sum of interior opposite angle ,so using it we get:
∠x = 61°+52°
∠x = 113°
Hence the value of ∠x is 113 degrees and y is 67 degrees.
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The answer is gonna be (4,3) .
Answer:
$175
Step-by-step explanation:
3.5 x 50 = $175
Answer:
The height is 12.9m
Step-by-step explanation:
First we have to find the distance from the corner of the flag to the opposite corner, for this we will use Pythagoras
In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides
h² = s1² + s2²
h² = 10² + 20²
h² = 100 + 400
h² = 500
h = √500
h = 22.36
Now that we know this measurement we can calculate the height of the flagpole
well to start we have to know the relationship between angles, legs and the hypotenuse
α = 30
a: adjacent = 22.36
o: opposite = ?
h: hypotenuse
sin α = o/h
cos α= a/h
tan α = o/a
we see that it has (angle, adjacent, opposite)
is the tangent
tan α = o/a
tan 30 = o/22.36
tan30 * 22.36 = o
12.9 = o
The height is 12.9m