Given a plane:
normal vector <2,4,-3>
passes through point (-1,3,5)
The equation of the plane is
Π : 2(x-(-1))+4(y-3)-3(z-5)=0
expand and simplify
Π : 2x+4y-3z+5=0
Answer:
Here we will use the relationships:



And a number:

is between 0 and 1 if a is positive and larger than 1, and n is negative.
if a is positive and 0 < a < 1, then we need to have n positive such that:
0 < a^n < 1
A) 
This is between zero and 1,
B) 
This is greater than 1, because the exponent is positive.
C) 
Because a is smaller than 1, and the exponent is positive, then the expression is between 0 and 1.
D) 
The exponent is negative (and pair) then the expression is between 0 and 1.
Remember that when the exponent is pair, we always have that:
(-N)^m = (N)^m
So (-7)^-2 = 7^-2
I'm assuming 7 Units
Step-by-step explanation:
i dunno what you are measuring the distance with
The improper fraction would be 2071/1000
6300: The 3 is in the hundreds place so its value is 3*100=300
530: The 3 is in the tens place so its value is 3*10=30
The value is 10x as much since 300=30*10