You need 300 mL of a 65% alcohol solution. On hand, you have a 50% alcohol mixture. How much of the 50% alcohol mixture and pure
alcohol will you need to obtain the desired solution?
You will need
____ mL of the 50% solution
and
______ mL of pure alcohol.
1 answer:
Answer:
You will need 220 mL of the 60% solution and 80 mL of pure alcohol.
Step-by-step explanation:
Let 'x' be the amount of 50% alcohol solution and y the amount of pure alcohol.
Therefore:
(0.5x + y)/300 = 0.65 ⇒ 0.5x + y = 190
x + y = 300
Solving the sistem of equations:
x = 220 and y = 080
Therefore, You will need
220 mL of the 60% solution
and 80 mL of pure alcohol.
You might be interested in
Answer:
the first one is true:)
Step-by-step explanation:
Step-by-step explanation:
f(x) = x + 1
g(x) = -3x
h(x) = 5-x
find fogoh
first we find fog
f(g(x)) = -3x + 1
then we find fogoh = -3(5-x ) +1
= -15 + 3x +1
= 3x -14
Answer:
3x+2|=lpz(|−2x+4|)
Step-by-step explanation:
Slope = (y2 - y1) / (x2 - x1)
= (2 - 4 ) / (1 - 3 )
= -2/-2
= 1
Answer is A. 1
93 x 10^6 =
93 x 1,000,000 = 93,000,000