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weeeeeb [17]
3 years ago
8

H(x)=-5x^2+10x+15h(x)=−5x 2 +10x+15h, left parenthesis, x, right parenthesis, equals, minus, 5, x, squared, plus, 10, x, plus, 1

5 What is the height of the stone at the time it is thrown?
Mathematics
1 answer:
kkurt [141]3 years ago
5 0

Answer:

15 units

Step-by-step explanation:

Given the equation which models the path of a stone as:

H(x)=-5x^2+10x+15

At the time when the stone was thrown

x=0

Therefore:

H(0)=-5(0)^2+10(0)+15\\H(0)=15

The height of the stone at the time it is thrown is 15 units.

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wel

Answer:

95%: (3278.354 ; 3270.083)

99% : (3221.646 ; 3278.354)

Step-by-step explanation:

Given :

Sample size, n = 12

Mean, xbar = 3250

Sample standard deviation = √1000

The 95% confidence interval :

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Margin of Error = Tcritical * s/√n

Tcritical at 0.05, df=12-1 = 11 ;

Tcritical at 95% = 2.20

Hence,

Margin of Error = (2.20 * √1000/√12) = 20.083

Confidence interval : 3250 ± 20.083

Lower boundary = 3250 - 20.083 = 3229.917

Upper boundary = 3250 + 20.083 = 3270.083

2.)

The 99% confidence interval :

Mean ± Margin of error

Margin of Error = Tcritical * s/√n

Tcritical at 0.01, df=12-1 = 11 ;

Tcritical at 99% = 3.106

Hence,

Margin of Error = (3.106 * √1000/√12) = 28.354

Confidence interval : 3250 ± 28.354

Lower boundary = 3250 - 28.354 = 3221.646

Upper boundary = 3250 + 28.354 = 3278.354

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Answer:

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