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vodomira [7]
3 years ago
12

A culture started with 4,000 bacteria. After 2 hours it grew to 4400 bacteria. Predict how many bacteria will be present after 1

3 hours round your answer to the nearest whole number.
Mathematics
2 answers:
Art [367]3 years ago
5 0
 <span>idk why they want the dratted "k" . it is so simple w/o it ! 
in the form y = ab^x, a = 4000, b = 4400/4000 = 1.1, x = t/2 
N = 4000*1.1^(13/2) = 7432 <------ 
----------------- 
now you won't be satisfied with simplicity, so 
4400 = 4000e^2k 
e^2k = 1.1 
k = ln 1.1/2 = .0477 to 4 dp 
N(13) = 4000e^(13*.0477) = 7436 <------ 

note that apart from a roundabout way, you get a less accurate ans !</span>
Over [174]3 years ago
3 0

Answer:

7436

Step-by-step explanation:

y = ab^x

a = 4000

b = 4400/4000 = 1.1

x = t/2 

4400 = 4000e^2k 

e^2k = 1.1 

k = ln 1.1/2 = .0477 to 4 dp 

N(13) = 4000e^(13*.0477) = 7436


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Answer:

The required recursive formula is

f(n)= 500\times(1.4)^{n-1}\\

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Each year thereafter the number of leaves was 40% more than the year before so that means

Year \: 2 = 500(1+0.40) = 500\times 1.4\\

For the third year the number of leaves increase 40% than the year before so that means

Year \: 3 = 500\times 1.4(1+0.40) = 500 \times 1.4^{2}\\

Similarly for fourth year,

Year \: 4 = 500\times 1.4^{2}(1+0.40) = 500\times 1.4^{3}\\

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Let f(n) be the number of leaves on the tree in Mohameds back yard in the nth year since he started tracking it then general recursive formula is

f(n)= 500\times(1.4)^{n-1}\\

This is the required recursive formula to find the number of leaves for the nth year.

Bonus:

Lets find out the number of leaves in the 10th year,

f(10)= 500\times(1.4)^{10-1}\\\\f(10)= 500\times(1.4)^{9}\\\\f(10)= 500\times20.66\\\\f(10)= 10330

So there will be 10330 leaves in the 10th year.

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