Answer: The blue whale's weight is 150 times heavier than the narwhal's weight.
Step-by-step explanation:
Given: Weight of Blue whale = 
Weight of Narwhal = 
Number of times blue whale's weight is heavier than the narwhal's weight = 
![=\dfrac{3\times10^5}{2\times10^3}\\\\=1.5\times10^{5-3}\ \ \ [\dfrac{a^m}{a^n}=a^{m-n}]\\\\=1.5\times10^2\\\\=1.5\times100=150](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B3%5Ctimes10%5E5%7D%7B2%5Ctimes10%5E3%7D%5C%5C%5C%5C%3D1.5%5Ctimes10%5E%7B5-3%7D%5C%20%5C%20%5C%20%5B%5Cdfrac%7Ba%5Em%7D%7Ba%5En%7D%3Da%5E%7Bm-n%7D%5D%5C%5C%5C%5C%3D1.5%5Ctimes10%5E2%5C%5C%5C%5C%3D1.5%5Ctimes100%3D150)
Hence, the blue whale's weight is 150 times heavier than the narwhal's weight.
Answer:
Option 2
Step-by-step explanation:
I say option to because it is 990
Tahmid has 96 figures, Sandeep has 1/3 of it so
96(1/3) = 96/3 = 32
Sandeep has 32 figures
Tahmid 96 ; Sandeep 32
How many must tahmid give so they have the same figures?
First take the difference of the two so we know how many tahmid can give.
96-32 = 64
now they each have 32 and 64 give or keep. for each one tahmid gives, he must keep one himself so to match the number they both own. so we divide the number of 2, one part to give, the other part to keep himself.
64/2 = 32
So, Tahmid must give Sandeep 32 figures to have equal number of figures of 64 each.
Correct me if I’m wrong, I believe you have to add all of those numbers together. Then divide after and plug in those remaining digits
Answer:
<h2>7</h2><h2 />
Step-by-step explanation:
Diagonal = 
