Question

How do I solve -3(3+x)+(x-6)=-4 ?

Answer 1

$\huge\boxed{x=-\frac{11}{2}}$

Start by distributing the $-3$ to the $(3+x)$. $-3(3) + (-3)(x) + (x-6) = -4$

Multiply and simplify. $-9-3x+(x-6)=-4$

Rearrange the terms. $-3x+x-9-6=-4$

Combine like terms. $-2x-15=-4$

Add $15$ on both sides. $-2x=11$

Divide both sides of the equation by $-2$. $x=\boxed{-\frac{11}{2}}$