One solution
<h2>
Explanation:</h2>
For a system of linear equations in two variables, we could have three possible cases:
<h3>Case 1. No solution.</h3>
This happens when the lines are parallel and have different y-intercepts.
<h3>Case 2. One solution.</h3>
This happens when the lines intersect at a single point.
<h3>Case 1. Infinitely many solutions</h3>
This happens when the lines are basically the same having the same slope and y-intercept.
So, let's rewrite our lines in Slope-intercept form 
:
As you can see, they have different slopes and y-intercepts. So they will intersect at a single point which is the solution of the system. By using graphing tool we get that this point is (1.5, -1) as indicated in the figure below.
<h2>Learn more:</h2>
Parametric equations: brainly.com/question/10022596
#LearnWithBrainly
Answer:
Since the equation is a quadractic, the graph would be a parabola.
With a being -1, the parabola will represent a reflection of the y values. In other words, the parabola will be upside down and the vertex will be a maximum value. Ultimately, the <em>a </em>in the function doesn't determine the location of the vertex.
Since the k value is negative, that means the equation begins <em>y - (-k)</em>. The K value being negative restricts the transformation of the parabola to being down <em>k</em> number of units. The location of moving the parabola down places the vertex in the third or fourth quadrant.
The <em>h</em> value being positive means that the parabola is shifted to the right <em>h</em> number of units. For example, if the parabola <em>f(x) = x² </em>has a vertex at (0,0), the parabola <em>f(x) = (x-2)²</em> must have a vertex at (2,0) because 2 - 2 = 0. Shifting right places the vertex of the parabola in the first or fourth quadrant.
Therefore the k value and h value restrictions must overlap in the fourth quadrant.
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
I only help you because you have nezuko as profile picture
I only found 4 ways, hope this helps
The first step is to define the system of equations.
Take x and y as the cost of a small box and a large box respectively.
Solve the system.
A small box costs $4 and a large box costs $4 too.
