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dlinn [17]
2 years ago
7

the vertices of parallelogram abcd are A(4,0,3), B(3,4,-2),C(-2,0,1). find the coodrdinates of fourth vertices

Mathematics
1 answer:
lakkis [162]2 years ago
7 0

Given :

The vertices of parallelogram ABCD are A(4,0,3), B(3,4,-2),C(-2,0,1).

To Find :

The coordinates of fourth vertices.

Solution :

We know, the vertices are ABCD .

Let, point D is (x,y,z) .

Also, diagonals of a parallelogram bisect each other.

Let, point of intersection of daigonal is O.

Coordinates of O are :

O_x = \dfrac{4+(-2)}{2}= 1\\\\O_y = \dfrac{0+0}{2 } = 0 \\\\O_z = \dfrac{3+1}{2}= 2

O(1,0,2)

Value of point O through BD.

O_x = \dfrac{3+x}{2}\\\\x=-1\\\\O_y = \dfrac{4+y}{2}\\\\y = -4\\\\O_z= \dfrac{-2+z}{2}\\\\z = 6

Therefore, the fourth vertices is D( -1,-4,6 ).

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\boxed{question \: number \: \to 6} \\ \boxed{ w = 72} \\ \boxed{ x =144 } \\ \boxed{ y = 108}

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y  + w  + y + w = 360 \to \sum \: of \: angles \\ y = \:  \boxed{opp \:  y}  \to \: vertically \: opposite \: angles \: are \: equal \\ w = \:  \boxed{opp \:  w}  \to  \: the \: same \: reason \: as \: y\\ hence \to \\ 2(w+ y) = 360 \\ w + y = 180 \\ but \: 5w = 360 \to \: angles \: at \: a \: point \\ w =  \frac{360}{5}  \\  \boxed{w = 72} \\ therefore \to \\ w + y = 180 \\ 72 + y = 180 \\ y = 180 - 72 \\ \boxed{ y = 108}  \\ hence \:  \boxed{x} \: is \: given \: by \to \\y + x + y = 360 \to \: angles \: at \: a \: point \\108 + x + 108 = 360 \\ x = 360 - 216 \\ \boxed{ x = 144}

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