Answer:
Step-by-step explanation:
RS is congruent to RV because of SSA or side side angle. RT is congruent to RT is a given. Lines that are perpindicular have right angles which proves angle v=angle s at the same time
So what we do is
area that remains=total area-triangle area that was cut out
we need to find 2 things
total area
triangle area
total area=rectange=base times height
area=(3x+4) times (2x+3)
FOIL or distribute
6x^2+8x+9x+12=6x^2+17x+12
triangle area=1/2 times base times height
triangle area=1/2 times (2x+2) times (x-2)=
(x+2) times (x-2)=x^2+2x-2x-4=x^2-4
so
total area=6x^2+17x+12
triangle area=x^2-4
subtract
area that remains=total area-triangle area that was cut out
area that remains=6x^2+17x+12-(x^2-4)=
6x^2+17x+12-x^2+4=
6x^2-x^2+17x+12+4=
5x^2+17x+16
area that remains is 5x^2+17x+16
8-5=3 is the remaining half
weekly allowance=2(1÷2) where (1÷2) is 3
2×3=6
The weekly allowance should be 6.
Answer:
The first table
Step-by-step explanation: The x values don't repeat which makes it a function
9514 1404 393
Answer:
A. x² -4
B. 2x² +8
Step-by-step explanation:
The area of a square is the square of the side lengths. That means the area of each large square is x², since it has a side length of x.
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A. The area of 4 small squares is subtracted from the area of the large square to find the shaded area:
x² -4×1² = x² -4 . . . area of Figure A
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B. The area of two small squares is added to the area of two large squares to find the shaded area:
2x² +2×2² = 2x² +8 . . . area of Figure B
