To solve this problem you must apply the proccedure shown below:
1. You have that the <span>parabola is 12 meters high at the vertex and at a height of 10 meters, the width is 8 meter.
2. Therefore, you have:
x^2=-4a(y^2-k)
4</span>^2=-4a(10-12)
16=-40a+48
16=8a
a=16/8
a=2
y=0
x^2=-8(0-12)
x^2=96
x=√96
x=9.79x2
x=19.58
3. Therefore, as you can see, the answer is: 19.58 meters.<span>
</span>
Answer:
- (x + 3)(x - 3)(x^2 -3x + 9)(x^2 + 3x + 9)
Step-by-step explanation:
<u><em>Use of formulas:</em></u>
- <em>a^2 - b^2 = (a + b)(a -b)</em>
- <em>a^3 + b^3 = (a + b)(a^2 - ab + b^2)</em>
- <em>a^3 - b^3 = (a - b)(a^2 + ab + b^2)</em>
<u>Given the expression: </u>
<u>Factoring 729</u>
<u>Factoring the expression </u>
- x^6 - 3^6 =
- (x^3)^2 - (3^3)^2 =
- (x^3 + 3^3)(x^3 - 3^3) =
- (x + 3)(x^2 -3x + 9)(x - 3)(x^2 + 3x + 9) =
- (x + 3)(x - 3)(x^2 -3x + 9)(x^2 + 3x + 9)
9514 1404 393
Answer:
Step-by-step explanation:
Adding the same number to both sides of the equation is an acceptable move. The addition property of equality tells Grace that the value of the variable will remain unchanged by such a move.
Her new equation would be ...
2x +20 +10 = 15 +10
2x +30 = 25 . . . . the result of Grace's move
_____
<em>Additional comment</em>
There may be very good reasons why Grace would want to do that. If solving the equation is Grace's intent, that move would be counterproductive. For the purpose of solving the equation, it would be more productive to either subtract 20 from both sides, or divide both sides by 2. These steps would give, respectively, ...
2x = -5
x +10 = 7.5
Answer:
b) 10
Step-by-step explanation:
(3×10+46)+14 = 90
<em>Hope this helps!!!!!</em>