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never [62]
3 years ago
11

What would be the awnsers

Mathematics
1 answer:
Tomtit [17]3 years ago
6 0

Answer:

I think the answer is

x=4

y=6

Step-by-step explanation:

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The answer is 22.6 so the quotient would be between 22.0 and 23.0, hope this helps.
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How many tens are in 60,000
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PLEASE HELP! I WILL MARK TOU AS BRAINLEIST!
san4es73 [151]

Answer:

a.Z(-2,1)

b.Z(1,1)

c.Z(-3,2)

Step-by-step explanation:

z(-2,3)

Imagine this point on a graph.

Translate it down two units :

the x stays -2, by going down the y decreases 2 so 3-2=1

Z(-2,1)

Translate Right three units : I'm assuming that we use the answer from the first translation

Z(-2,1)

The y doesn't change this time the x increases 3 since we're moving to the right.

Z(1,1)

Translate up 1 and left 4:

Z(1,1)

by moving up one we have Z(1,2) then by moving 4 to the left we get Z(-3,2)

Hope this helps :)

6 0
3 years ago
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Please please help :(
Vinvika [58]
-6 7/8 /(-3 3/4)
55/8X4/15
11/6
1 5/6
6 0
3 years ago
Suppose a consumer product researcher wanted to find out whether a highlighter lasted less than the manufacturer's claim that th
11111nata11111 [884]

Answer:

The null hypothesis is H_0: \mu = 14

The alternate hypothesis is H_a: \mu < 14

The test statistic is t = -1.95.

The p-value is of 0.0292. This means that for a level of significance of 0.0292 and higher, there is sufficient evidence to conclude that the  highlighters wrote for less than 14 continuous hours.

Step-by-step explanation:

Suppose a consumer product researcher wanted to find out whether a highlighter lasted less than the manufacturer's claim that their highlighters could write continuously for 14 hours.

At the null hypothesis, we test if the mean is 14 hours, that is:

H_0: \mu = 14

At the alternate hypothesis, we test if the mean is less than 14 hours, that is:

H_a: \mu < 14

The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.

14 is tested at the null hypothesis:

This means that \mu = 14

X = 13.6 hours, s = 1.3 hours. Sample of 40:

In addition to the values of X and s given, we have that n = 40

Test statistic:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{13.6 - 14}{\frac{1.3}{\sqrt{40}}}

t = -1.95

The test statistic is t = -1.95.

P-value:

The p-value of the test is the probability of finding a sample mean lower than 13.6, which is a left tailed test, with t = -1.95 and 40 - 1 = 39 degrees of freedom.

Using a calculator, the p-value is of 0.0292. This means that for a level of significance of 0.0292 and higher, there is sufficient evidence to conclude that the  highlighters wrote for less than 14 continuous hours.

5 0
2 years ago
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