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Sorry for not really answering you're question. I have no idea. I'm sorry.
X = -0.25 and x = -2^-2
I’m not sure if this helps
Answer:
Error:
not 
Solution:x=0 and 3
Step-by-step explanation:
We have to find the error and correct answer
Given:![2ln x=ln(3x)-[ln9-2ln(3)]](https://tex.z-dn.net/?f=2ln%20x%3Dln%283x%29-%5Bln9-2ln%283%29%5D)
![lnx^2=ln(3x)-[ln9-ln3^2]](https://tex.z-dn.net/?f=lnx%5E2%3Dln%283x%29-%5Bln9-ln3%5E2%5D)
Using the formula

![lnx^2=ln(3x)-[ln9-ln9]](https://tex.z-dn.net/?f=lnx%5E2%3Dln%283x%29-%5Bln9-ln9%5D)





Therefore, x=0 and x=3
But last step in the given solution

It is wrong this property is used when
then

Hence, the student wrote
instead of
and solution is given by
x=0 and x=3
Ok got it. If you have any questions just ask in the chat below :)
Answer:
The answer is 3.2 E 3 or 3.2 x 10^3
You move back 3 spaces which is 3.2, since you moved back 3 spaces, you put 3 as the power/exponet.
To be more satisfied, 3.2 is your base number, it is the big number Below the power/exponent. The power/exponent is 3, you moved 3 spaces and you moved to the left, so it is represented as a positive power/exponent.
Hope this helps.