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Yanka [14]
3 years ago
6

Lisa wants to frame her little brothers drawings is 43.5 cm by 934 mm how many cm of wood framing will she need

Mathematics
2 answers:
umka2103 [35]3 years ago
5 0

951 is your answerrrrr


Ira Lisetskai [31]3 years ago
3 0
Okay, her brother drawings are 43.5 cm by 934 mm.

First thing we need to do id get alike measurements. 
1 cm = 10 mm.

Multiply 43.5 by 10          934 mm = 435

Now since we are framing something we need to find the perimeter. 

Write an equation: P= cm of wood= w     

w= 2(43.5)+2(435)

Simplify:
w=951

Answer:
951 cm of wood
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Find the local maximum and minimum values and saddle point(s) of the function.
iogann1982 [59]
f(x,y)=9e^y(y^2-x^2)
\nabla f=\left\langle-18xe^y,9ye^y(2+y)\right\rangle

Critical points occur where the gradient is zero. This is guaranteed whenever x=0 and either y=0 or y=-2.

The Hessian matrix for this function looks like

H(x,y)=\begin{bmatrix}f_{xx}&f_{xy}\\f_{yx}&f_{yy}\end{bmatrix}=\begin{bmatrix}-18e^y&-18xe^y\\-18xe^y&9e^y(2-x^2+4y+y^2)\end{bmatrix}

and has determinant

|H(x,y)|=-162e^{2y}(2+x^2+4y+y^2)

Maxima occur whenever the determinant is positive and f_{xx}. Minima occur whenever both the determinant and f_{xx} are positive. Saddle points occur whenever the determinant is negative.

At (0,0), you have a saddle point since the determinant reduces to -324, so (0,0,0) is the saddle point.

At (0,-2), the determinant is \dfrac{324}{e^4}>0 and f_{xx}(0,-2)=-\dfrac{18}{e^2}, so \left(0,-2,\dfrac{36}{e^2}\right) is a local maximum.

No other critical points remain, so you're done.
4 0
3 years ago
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mars1129 [50]
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A tree is 4<br> is 4.4 feet tall. It is expected to grow by 1 feet per year.
LekaFEV [45]

Answer:

it should be 10.4 in 6 years.

Step-by-step explanation:

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6 0
3 years ago
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3 years ago
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BigorU [14]

Answer:

see image

Step-by-step explanation:

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