Question

(3a2 – 5ab + b2) + (–3a2 + 2b2 + 8ab) Which of the following shows the sum of the polynomials rewritten with like terms grouped together? [3a2 + (–3a2)] + (–5ab + 8ab) + (b2 + 2b2) [3a2 + (–3a2)] + (–5ab + 2b2) + (b2 + 8ab) [3a2 + 3a2] + (5ab + 8ab) + (b2 + 2b2) [3a2 + 3a2] + (5ab + 2b2) + (b2 + 8ab)

Answer 1

Answer:

Option 1st is correct

$[(3a^2+(-3a^2)]+(-5ab+8ab)+ (b^2+2b^2)$

Step-by-step explanation:

Given the expression:

$(3a^2-5ab+b^2)+(-3a^2+2b^2+8ab)$

Like terms are those which have same variable to the same powers.

Open the bracket:

$3a^2 -5ab+b^2+(-3a^2)+2b^2+8ab$

⇒$[(3a^2+(-3a^2)]+(-5ab+8ab)+ (b^2+2b^2)$

Therefore, the sum of the polynomials rewritten with like terms grouped together is:

$[(3a^2+(-3a^2)]+(-5ab+8ab)+ (b^2+2b^2)$

Answer 2

[3a2 + (–3a2)] + (–5ab + 8ab) + (b2 + 2b2)