Answer:
Below in bold.
Step-by-step explanation:
y = x^2-8x+6
y = (x - 4)^2 - 16 + 6
y = (x - 4)^2 - 10
So the vertex is at (4, -10)
The coefficient of x^2 of this function is 1 ( positive) so there will be a minimum value.
Minimum value = -10.
x-intercepts:
(x - 4)^2 - 10 = 0
(x - 4)^2 = 10
x - 4 = +/- √10
x = 4 +/- √10
- therefore there are 2 x-intercepts.
Solve the inequality , find the max possible value for the variable.
3t + 1 < t + 12
2t < 11
t < 5.5
t_max = 5.5
For the second question just solve as two separate inequalities
4 +2 < x <= 7 + 2
6 <x <= 9
x in ]6, 9]
Answer:
The answer is C. x = 5
Step-by-step explanation:
Plug in 5 and mutiply it by 4 and get 20, 20 plus 1 is 21.
Divide it by 25 witch is the height then find the square root
Answer:
Answer is y = 6
Step-by-step explanation:
Solve for y.
