First, we'll solve A.
2 x2 = 4
3 x2 = 9
3x2=6, not 9.
So it is not A.
5 x2 = 10
7 x2 = 11
7x2=14, not 11.
So B. is out too.
It isn't D. because 12/9 is improper and 3/4 isn't.
So C. is left.
4 x2 = 8
6 x2 = 12
hope it helps!
Answer:
True
Step-by-step explanation:
- One way to find the least common multiple of two or more numbers is to first multiply each by 1, 2, 3, etc.
Square root 3/2
Decimal form: 086602540
Mapping A would be the one