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9966 [12]
3 years ago
10

PLEASE SOLVE FOR B. PLEASE HELP VERY URGENT!

Mathematics
1 answer:
aleksklad [387]3 years ago
4 0

Answer:

b1 = (2A/ h) - b2

Step-by-step explanation:

A  = 1/2 h(b1 + b2)

b1 + b2 = A / 1/2h = 2A/h

b1 = (2A/ h) - b2

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Which of the following ordered pairs belongs to the graph of f(x)
Lera25 [3.4K]

Answer:

The second choice, (-1,\, 12).

Step-by-step explanation:

Note, that the expression y = f(x) is an equation. A point (x,\, y) is on the graph of y = f(x)\! if and only if the value of x and y satisfy this equation; that is: in other words, the y\!-coordinate of that point (the second number in the tuple) should be equal to f(x), which is equal to (-3\, x +9) (evaluated where x\! is equal to the first number in the tuple.

For each tuple in the choices, calculate the value of f(x) where x is equal to the first number of each tuple. Compare the result to the second number in that tuple. That choice corresponds to a valid point on y = f(x) only if these two numbers match.

  • First choice: x = 1, f(x) = f(1) = -3 + 9 = 6. That's not the same as the second number, -10. Therefore, this point isn't on the graph of y = f(x).
  • Second choice: x = -1, f(x) = f(-1) = (-3)\times (-1) + 9 = 3 + 9 = 12. That matches the second number in the tuple. Therefore, this point is on the graph of y = f(x).
  • Third choice: x = 2, f(x) = f(2) = (-3)\times 2 + 9 = 3. That's not the same as the second number, (-3). Therefore, this point isn't on the graph of y = f(x).
  • Fourth choice: x = -2, f(x) = f(-2) = (-3)\times (-2) + 9 = 15. That's not the same as the second number, 13. Therefore, this point isn't on the graph of y = f(x).
4 0
3 years ago
What statement is true about f(x)=-2/3|x+4|-6?
grandymaker [24]

Answer: The graph of f(x) is horizontally stretched  

7 0
3 years ago
Find the derivative of f(x) = 6x + 2 at x = 1.
earnstyle [38]
f'(x_0)=\lim\limits_{x\to x_0}\dfrac{f(x)-f(x_0)}{x-x_0}\\\\f(x)=6x+2;\ x_0=1\\\\f'(1)=\lim\limits_{x\to x_0}\dfrac{(6x+2)-(6\cdot1+2)}{x-1}=\lim\limits_{x\to x_0}\dfrac{6x+2-8}{x-1}\\\\=\lim\limits_{x\to x_0}\dfrac{6x-6}{x-1}=\lim\limits_{x\to x_0}\dfrac{6(x-1)}{x-1}=\lim\limits_{x\to x_0}6=6\\\\\\Answer:\boxed{f'(1)=6}
6 0
3 years ago
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Please help solve for the second section
MaRussiya [10]

It is the 3rd option from the bottom of the 2nd collum.The numbers switch places when the letter changes (from b to b') but they remain the same.

6 0
3 years ago
The quotient of x and 6 divided by 9. where does The x and 6 go on the top or the bottom?​
nirvana33 [79]

Answer: x and 6 goes on the top

Step-by-step explanation:

You are dividing 9 into x and 6, therefore x and 6 is the dividend and 9 is the divisor.

5 0
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