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tresset_1 [31]
3 years ago
14

How to solve -w+4(w+3)=-12

Mathematics
2 answers:
san4es73 [151]3 years ago
4 0
-w+4(w+3)=-12
-w+4w+12=-12
3w+12=-12
    -12   -12
3w=-24
(3w)/3=-24/3
w=-8
Mars2501 [29]3 years ago
3 0
-w+4(w+3)=-12
-w+4w+12=-12
3w=-12-12
3w=-24
w=-8
HOPE I HELPED!!!
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Johnny earns $5 per day delivering newspapers. What equation shows how much money m he earns delivering papers for d days
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What is the X-coordinate of the Point (6,8)?
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Read 2 more answers
URGENT!!!!<br> Please add workings out
Artist 52 [7]

Answer: 26.457 cm

Explanation:

First, the height of an equilateral triangle of side length a is:

h = \frac{\sqrt{3} }{2}*a

In this case, the side-length of the triangles is a = 10cm, then the height will be:

h = \frac{\sqrt{3} }{2}*10cm = 8.66cm

Now we can think on a triangle rectangle such that:

Point A and point F are vertexes of the triangle.

The line we want to find, the line from A to F, is the hypotenuse.

One cathetus is a the height of the triangle, that comes down from point A, the length of this cathetus is 8.66cm

The other cathetus is equal to half the side length of the triangles (5cm) plus the segments BD and DF (of 10cm each)

Then the length of this cathetus is 10cm + 10cm + 5cm = 25cm

Now, we can remember the Pythagorean theorem.

If H is the hypotenuse, and A and B are the catheti, then we have:

A^2 + B^2 = H^2

In this case, we know the length of both cathetus, and want to know the length of the hypotenuse, then:

(25cm)^2 + (8.66cm)^2 = H^2

√( (25cm)^2 + (8.66cm)^2) = H = 26.457 cm

Then the line from A to F is 26.457 cm

6 0
2 years ago
X²+y²=25 xy=12 find the value of (3x+3y)²​
Papessa [141]

Answer:

Step-by-step explanation:

(a + b)²=a²+2ab+b²

(3x+3y)²= (3x)²+2*3x*3y+(3y)²

=9x² + 18xy + 9y²

=9x²  + 9y² + 18xy

= 9*(x²+y²) +18xy

=9*25 + 18*12

=225 + 216

=441

7 0
3 years ago
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