Answer:
Step-by-step explanation:
2x²+4x -16 = 2(x²+2x-8); factor 2
= 2(x+4)(x-2) ;factor the quadratic equation
4x²-16 = 4(x²-4) ; factor 4
=4(x²- 2²) ; rewrite 4 as 2²
= 4(x-2)(x+2); now use the difference of two squares a²-b²=(a-b)(a+b)
so now we have:
; simplify (x-2) from numerator and denominator
and 2/4 as 1/2
Answer:
Step-by-step explanation:
So we need to find an equation of a line that crosses the point (6,-4) and is perpendicular to y = -2x -3.
First, let's find the slope of the line we want to write. The line we want is perpendicular to y = -2x -3. Recall that if two lines are perpendicular to each other, their slopes are negative reciprocals of each other. What this means is that:
Plug -2 for one of the slopes.
Divide by -2 to find the slope of our line.
Thus, our line needs to have a slope of 1/2.
Now, let's use the point-slope form. The point-slope form is given by:
Plug in 1/2 for the slope m and let's let our point (6,-4) be x₁ and y₁. Thus:
Simplify and distribute:
Subtract 4 from both sides:
The above is the equation that passes the point (6,-4) and is perpendicular to y = -2x -3.