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ehidna [41]
3 years ago
5

The trapezoid below has an area of 1575 cm. What equation could you solve to find the height of the trapezoid

Mathematics
1 answer:
Finger [1]3 years ago
3 0
The trapezoid formula is 1/2 (base 1+ base 2) x height. So if you work backwards you should be able to find the height. Could you give the base measurements?
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Which number produces an irrational number when multiplied by 1/3
MArishka [77]

We can simply observe that.

  1. 0.777... is rational, because it is a number with infinite but repeating decimal part.
  2. 1/3 is rational, because it's the division between two integers
  3. -\sqrt{16}=-4, so this is rational as well.

Since the product of two rational numbers is always rational, we have that

0.\bar{7}\cdot \dfrac{1}{3},\quad \dfrac{1}{3}\cdot \dfrac{1}{3},\quad -4\cdot \dfrac{1}{3}

are all rationals, since they are the product of two rationals.

On the other hand, we have

\sqrt{27}=\sqrt{9\cdot 3}=3\sqrt{3}

and thus

3\sqrt{3}\cdot \dfrac{1}{3}=\sqrt{3}

which is irrational.

3 0
3 years ago
Find four consecutive integers with a sum of 106.
grandymaker [24]
4 consecutive integers...
x, x + 1, x + 2, x + 3

x + x + 1 + x + 2 + x + 3 = 106
4x + 6 = 106
4x = 106 - 6
4x = 100
x = 100/4
x = 25

x + 1 = 25 + 1 = 26
x + 2 = 25 + 2 = 27
x + 3 = 25 + 3 = 28

ur 4 integers are : 25,26,27,28
6 0
3 years ago
Jenny earned a 77 on her most recent test. Jenny’s score is no less than 5 points greater than Four-fifths of Terrance’s score.
lina2011 [118]

77 5 + 4/5t

Is the answer!

4 0
3 years ago
Read 2 more answers
Which is the graph of the equation y-1=2/3(x-3)? <br> PLEASE ANSWER ASAP
alexgriva [62]

Answer:

Graph #1

Step-by-step explanation:

Compare your

y - 1 = (2/3)(x - 3) to

y - k = m(x - h).  We see that k = 1 and h = 3.

Thus, (1, 3) is a point on the graph.  This matches Graph #1.  

Note: Graph #1 and Graph #3 appear to be the same.  Why?

8 0
3 years ago
Read 2 more answers
How do you find the area of this composite figure?
Illusion [34]
If you notice the picture below

the composite figure is just a trapezoid sitting on top of a rectangle
and then, the rectangle has a triangular hole in it

so.. get the area of the trapezoid   \bf \textit{area of a trapezoid}=A=\cfrac{h}{2}(a+b)\qquad &#10;\begin{cases}&#10;h=height\\&#10;a,b=\textit{parallel sides or bases}&#10;\end{cases}

then get the area of the rectangle, which is just a 12x14
and then get the area of the triangle, which surely you know is 1/2 bh

then, subtract the triangle's area from the rectangle's area

and whatever is left, namely the difference, add that to the area of the trapezoid, and that's the composite's area

namely the area of the trapezoid plus the rectangle's, minus the triangle's

6 0
3 years ago
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