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3 years ago

6

All positive integers $t$ such that $1.2t \leq 9.6$?

1 answer:

serious [3.7K]3 years ago

7 0

Haha me don’t know sorry okay

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Your teacher asks the class to evaluate the expression. Your classmate gives an incorrect answer of 256. Evaluate the expression

Leya [2.2K]

Answer:

What expression?

Step-by-step explanation:

8 0

3 years ago

∫(x+1)/(x2+2)2x−3dx need help with this question. can you show the process

kenny6666 [7]

do you need to include the wiggle infront of the first bracket? if not;

(x+1) ÷ [(x^2+2) x (2x-3dx)]

x^2 x 2x = 2x^3

x^2 x -3dx = -3dx^3

2 x 2x = 4x

2 x -3dx = - 6dx

i cant find a way to make it equal 0 so i think the answer is just

x+1 over 2x^3 - 3dx^3 + 4x - 6dx as a fraction

4 0

3 years ago

2. In how many ways can 3 different novels, 2 different mathematics books and 5 different chemistry books be arranged on a books

insens350 [35]

The number of ways of the books can be arranged are illustrations of permutations.

When the books are arranged in any order, the number of arrangements is 3628800
When the mathematics book must not be together, the number of arrangements is 2903040
When the novels must be together, and the chemistry books must be together, the number of arrangements is 17280
When the mathematics books must be together, and the novels must not be together, the number of arrangements is 302400

The given parameters are:

$\mathbf{Novels = 3}$

$\mathbf{Mathematics = 2}$

$\mathbf{Chemistry = 5}$

<u />

<u>(a) The books in any order</u>

First, we calculate the total number of books

$\mathbf{n = Novels + Mathematics + Chemistry}$

$\mathbf{n = 3 + 2 + 5}$

$\mathbf{n = 10}$

The number of arrangement is n!:

So, we have:

$\mathbf{n! = 10!}$

$\mathbf{n! = 3628800}$

<u>(b) The mathematics book, not together</u>

There are 2 mathematics books.

If the mathematics books, must be together

The number of arrangements is:

$\mathbf{Maths\ together = 2 \times 9!}$

Using the complement rule, we have:

$\mathbf{Maths\ not\ together = Total - Maths\ together}$

This gives

$\mathbf{Maths\ not\ together = 3628800 - 2 \times 9!}$

$\mathbf{Maths\ not\ together = 2903040}$

<u>(c) The novels must be together and the chemistry books, together</u>

We have:

$\mathbf{Novels = 3}$

$\mathbf{Chemistry = 5}$

First, arrange the novels in:

$\mathbf{Novels = 3!\ ways}$

Next, arrange the chemistry books in:

$\mathbf{Chemistry = 5!\ ways}$

Now, the 5 chemistry books will be taken as 1; the novels will also be taken as 1.

Literally, the number of books now is:

$\mathbf{n =Mathematics + 1 + 1}$

$\mathbf{n =2 + 1 + 1}$

$\mathbf{n =4}$

So, the number of arrangements is:

$\mathbf{Arrangements = n! \times 3! \times 5!}$

$\mathbf{Arrangements = 4! \times 3! \times 5!}$

$\mathbf{Arrangements = 17280}$

<u>(d) The mathematics must be together and the chemistry books, not together</u>

We have:

$\mathbf{Mathematics = 2}$

$\mathbf{Novels = 3}$

$\mathbf{Chemistry = 5}$

First, arrange the mathematics in:

$\mathbf{Mathematics = 2!}$

Literally, the number of chemistry and mathematics now is:

$\mathbf{n =Chemistry + 1}$

$\mathbf{n =5 + 1}$

$\mathbf{n =6}$

So, the number of arrangements of these books is:

$\mathbf{Arrangements = n! \times 2!}$

$\mathbf{Arrangements = 6! \times 2!}$

Now, there are 7 spaces between the chemistry and mathematics books.

For the 3 novels not to be together, the number of arrangement is:

$\mathbf{Arrangements = ^7P_3}$

So, the total arrangement is:

$\mathbf{Total = 6! \times 2!\times ^7P_3}$

$\mathbf{Total = 6! \times 2!\times 210}$

$\mathbf{Total = 302400}$

Read more about permutations at:

brainly.com/question/1216161

8 0

2 years ago

3) Rita has 3/4 m of Ifugao cloth. She used 2/3 m for placement. What part

enot [183]

Answer:

$Unused = \frac{1}{12}m$

Step-by-step explanation:

Given

$Total= \frac{3}{4}m$

$Used= \frac{2}{3}m$

Required

Determine the part left

The part left is calculated using:

$Used + Unused = Total$

$Unused = Total - Used$

$Unused = \frac{3}{4}m - \frac{2}{3}m$

Take LCM

$Unused = \frac{9m - 8m}{12}$

$Unused = \frac{1m}{12}$

$Unused = \frac{1}{12}m$

6 0

3 years ago

Jake ate 4/8 of a pizza. Millie ate 3/8 of the same pizza. How much of the pizza was eaten by jake and Millie?

Alexus [3.1K]

I believe they both had 7/8

3 0

3 years ago