Please help me I’ll give brainiest
2 answers:
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Complete the table for the function y = 0.1^x
The first step: plug values from the left column into the ‘x’ spot in the formula <u>y=0.1^x</u>.
* 0.1^-2 : We can eliminate the negative exponent value by using the rule a^-1 = 1/a. Keep this rule in mind for future problems. (0.1^-2 = 1/0.1 * 0.1 = 100).
* 0.1^-1 = 1/0.1 = 10
* 0.1^0 = 1 : (Remember this rule: a^0 = 1)
* 0.1^1 = 0.1
Our list of values: 100, 10, 1, 0.1
Now, we can plug these values into your table:
The points can now be graphed. I will paste a Desmos screenshot; try to see if you can find some of the indicated (x,y) values: [screenshot is attached]
I hope this helped!
Answer:
Range is {y | y ≥ –11}
Step-by-step explanation:
This is quadratic equation.
<em>A quadratic equation's range can be found if we find the vertex.</em>
For quadratic equations that have a positive number in front of , it is upward opening and thus <u>all the numbers greater than or equal to the minimum value of vertex is the range.</u>
The formula for vertex of a parabola is:
Vertex =
Where,
is the coefficient of
is the coefficient of
From our equation given, and
Now, coordinate of vertex is
coordinate of the vertex IS THE MINIMUM VALUE that we want. We get this by plugging in the
value [
] into the equation. So we have:
Hence, the range would be all numbers greater than or equal to
Third answer choice is the right one.