Whats the 4th value in 456 210

Solve: 3a - 2.4 = 5.1 a = _____

Delicious77 [7]

Answer:

a=2.5

Step-by-step explanation:

3a-2.4=5.1 Add the like terms ( plus 2.4 cancels out -2.4)

+2.4 +2.4

3a=7.5 Now divide by 3

/3 /3

a=2.5

7 0

2 years ago

Original price: $48.50<br> Sales tax: 6%

Rainbow [258]

Answer:

$51.41

Step-by-step explanation:

trust

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Csf%20%5Clim_%7Bx%20%5Cto%20%5Cinfty%7D%20%5Ccfrac%7B%5Csqrt%7Bx-1%7D-2x%20%7D%7Bx-7%7D" id=

BARSIC [14]

<h3>Answer: -2</h3>

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Work Shown:

$\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{x-1}-2x }{ x-7 }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \frac{1}{x}\left(\sqrt{x-1}-2x\right) }{ \frac{1}{x}\left(x-7\right) }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \frac{1}{x}*\sqrt{x-1}-\frac{1}{x}*2x }{ \frac{1}{x}*x-\frac{1}{x}*7 }\\\\\\$

$\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x^2}}*\sqrt{x-1}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x^2}*(x-1)}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x}-\frac{1}{x^2}}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \frac{ \sqrt{0-0}-2 }{ 1-0 }\\\\\\\displaystyle L = \frac{-2}{1}\\\\\\\displaystyle L = -2\\\\\\$

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Explanation:

In the second step, I multiplied top and bottom by 1/x. This divides every term by x. Doing this leaves us with various inner fractions that have the variable in the denominator. Those inner fractions approach 0 as x approaches infinity.

I'm using the rule that

$\displaystyle \lim_{x\to\infty} \frac{1}{x^k} = 0\\\\\\$

where k is some positive real number constant.

Using that rule will simplify the expression greatly to leave us with -2/1 or simply -2 as the answer.

In a sense, the leading terms of the numerator and denominator are -2x and x respectively. They are the largest terms for each, so to speak. As x gets larger, the influence that -2x and x have will greatly diminish the influence of the other terms.

This effectively means,

$\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{x-1}-2x }{ x-7 } = \lim_{x\to\infty} \frac{ -2x }{ x} = -2\\\\\\$

I recommend making a table of values to see what's going on. Or you can graph the given function to see that it slowly approaches y = -2. Keep in mind that it won't actually reach y = -2 itself.

5 0

2 years ago

The strip below is cut into 9 equal bars.<br> Shade 2/3 of this strip.

Anna35 [415]

Answer:

Shade 6 bars.

Step-by-step explanation:

You are asked to shade 2/3 of the strip. It is given that the strip has 9 equal parts. Multiply the number and fraction together:

$9 * \frac{2}{3} = \frac{9}{1} * \frac{2}{3} = \frac{9 * 2}{1 * 3} = \frac{18}{3} = 6$

You will shade 6 of the 9 bars given.

~

5 0

1 year ago

An inconsistent system of linear equations has blank solutions and the lines graphed will blank

kvv77 [185]

An inconsistent system graphs two parallel lines. These parallel lines will never cross. Therefore there are no solutions.

8 0

2 years ago