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Brut [27]
3 years ago
11

I need help with these questions! I need to finish them quick. Please and thank you!

Mathematics
1 answer:
lidiya [134]3 years ago
3 0

Answer:

33ft^2

Step-by-step explanation:

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f(x)= 1 / x-3 g(x)= 3x + 1/x A. Use composition to prove whether or not the functions are inverses of each other. B. Express the
Alisiya [41]

Step-by-step explanation:

(A) To find inverse of f(x) = y = 1 / x - 3 :

<u>Transform in terms of x</u>

y = 1 / x - 3

x - 3 = 1 / y

x = 3 + 1 / y

<u>Exchange x with y</u> :

{f}^{ - 1} (x) = 3 +  \frac{1}{x}

Therefore, g(x) is not inverse of f(x) and vice versa.

(B)

Domain of f(x) = R - {3}

Domain of g(x) = R - {0}

7 0
3 years ago
Find a third point on the line that passes through (4, 1) and (0, 3)
iragen [17]
Ijdbquhbkjhqbciuqhviucvqeuvbciuqvwiduc
6 0
3 years ago
HELP ME PLZZZZ!!!!!<br><br><br> It’s just 21 and 22
galina1969 [7]

Answer:

21) 12 cm

22) 5.9 cm

Step-by-step explanation:

21) The base is 10, and if the other two sides are congruent and the perimeter is 36, we can figure out with simple algebra that the sides are 13 cm long.

Half of 10 is 5, so we can use the pythagorean theorem.

5^2+x^2=13^2

Rearranging the variables we have 169-25=x^2

144=x^2

x can be plus or minus 12, but since negative length is impossible we find that x is positive 12 cm.

22) We want to use sine, because we have opposite and hypotenuse. A simple and easy way to memorize this is the SohCahToa method. If we have opposite (O) and hypotenuse (H) we have OH. Soh has the letters O and H, and the S means we should use sine.

sine 36=a/10

Plug this into a calculator or desmos scientific calculator to get a=5.9

7 0
3 years ago
Guys do anybody know the answer to this????????????????
sergejj [24]

Answer:

find where they intersect on the graph or find each line's individual equation and set them equivalent to eachother. x=2

8 0
2 years ago
Y’all I need help I need a good grade on this
Andreyy89

Answer:

SLOPE IS -3

Step-by-step explanation:

4-7 over 0-(-1)

3 0
2 years ago
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