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GuDViN [60]
3 years ago
6

Solve this with processes and teach me clearly.​

Mathematics
1 answer:
aivan3 [116]3 years ago
7 0

Answer: one.

Step-by-step explanation:

Let's break down the numerator first.

That ugly mess can be re-written as:

2^(2x+2y) times 2^(2y+2z) times 2^(2z+2x).    Recall that (a^b)+(a^c)=a^(b+c).

2^(2x+2y) times 2^(2y+2z) times 2^(2z+2x) equals 2^(4x+4y+4z).

Let's break down the denominator now.

That mess can be re-written as:

2^x times 2^y times 2^z.

That can be re-written as 2^(x+y+z).

2^(x+y+z) all to the 4th power equals 2^(4x+4y+4z).

The denominator and numerator equal one another.

Bam.

Ask if you have any questions.

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Genrish500 [490]

If x is a real number such that x3 + 4x = 0 then x is 0”.Let q: x is a real number such that x3 + 4x = 0 r: x is 0.i To show that statement p is true we assume that q is true and then show that r is true.Therefore let statement q be true.∴ x2 + 4x = 0 x x2 + 4 = 0⇒ x = 0 or x2+ 4 = 0However since x is real it is 0.Thus statement r is true.Therefore the given statement is true.ii To show statement p to be true by contradiction we assume that p is not true.Let x be a real number such that x3 + 4x = 0 and let x is not 0.Therefore x3 + 4x = 0 x x2+ 4 = 0 x = 0 or x2 + 4 = 0 x = 0 orx2 = – 4However x is real. Therefore x = 0 which is a contradiction since we have assumed that x is not 0.Thus the given statement p is true.iii To prove statement p to be true by contrapositive method we assume that r is false and prove that q must be false.Here r is false implies that it is required to consider the negation of statement r.This obtains the following statement.∼r: x is not 0.It can be seen that x2 + 4 will always be positive.x ≠ 0 implies that the product of any positive real number with x is not zero.Let us consider the product of x with x2 + 4.∴ x x2 + 4 ≠ 0⇒ x3 + 4x ≠ 0This shows that statement q is not true.Thus it has been proved that∼r ⇒∼qTherefore the given statement p is true.

8 0
3 years ago
The mean cost of a five pound bag of shrimp is 40 dollars with a standard deviation of 7 dollars. If a sample of 51 bags of shri
eimsori [14]

Answer:

P(|\bar{x}-40| > 0.6)=0.5404

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 40 dollars

Standard Deviation, σ = 7 dollars

Sample size,n = 51

We are given that the distribution of cost of shrimp is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling =

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{7}{\sqrt{51}} = 0.9801

P(sample mean would differ by true mean by more than 0.6)

P(|\bar{x}-40| > 0.6)\\\Rightarrow = 1-P(39.4

P(39.4 \leq x \leq 40.6) \\\\= P(\displaystyle\frac{39.4 - 40}{0.9801} \leq z \leq \displaystyle\frac{40.6-40}{0.9801})\\\\ = P(-0.6121 \leq z \leq 0.6121)\\= P(z \leq 0.6121) - P(z < -0.6121)\\= 0.7298 - 0.2702 =0.4596

P(|\bar{x}|-40 > 0.6)\\= 1-0.4596=0.5404

0.5404 is the required probability.

4 0
3 years ago
USE THE FREQUENCY DISTRIBUTION TO DETERMINE THE FOLLOWING:A) THE TOTAL NUMBER OF OBSERVATIONS.B) THE WIDTH OF EACH CLASS.C) THE
lutik1710 [3]

A) The total number is the sum of all the frequencies

2+5+8+12+11+6=44

Answer: 44

B) The width is (upper limit - lower limit) / 2

(35-21) / 2 = 7

(50-36) / 2 = 7

(65-51) / 2 = 7

(80-66) / 2 = 7

(95-81) / 2 = 7

(110-96) / 2 = 7

Answer: the width is 7

C) The midpoint is the lower limit + the width

36+7=43

Answer: the midpoint is 43

D)The modal is the class with more frequency

In this case 66-80 with 12

Answer: class 66-80

E) We use the width formula

lower limit = 111

width = 7

upper = (width * 2) - lower

upper = (7 * 2) + 111

upper = 125

Answer: class 111-125

4 0
1 year ago
Solve for kkk. \dfrac{3}{k} = \dfrac{4}{5} k 3 ​ = 5 4 ​ start fraction, 3, divided by, k, end fraction, equals, start fraction,
sweet-ann [11.9K]

Answer: \dfrac{15}{4}

Step-by-step explanation:

Given

\Rightarrow \dfrac{3}{k}=\dfrac{4}{5}

Apply cross-multiplication

\Rightarrow K=3\times \dfrac{5}{4}=\dfrac{15}{4}\\\\\Rightarrow k=3\ \dfrac{3}{4}

The value of k is \dfrac{15}{4}\ \text{or}\ 3\ \dfrac{3}{4}

5 0
3 years ago
Read 2 more answers
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<span>A = hours for plan A
B = hours for plan B</span>

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Tuesday: 2A + 3B = 3</span>

use elimination by multiplying the 2nd equation by 3.

Doing that we get 3(2A + 3B = 3) = 6A + 9B = 9

<span>So the two equations are now:
6A + 9B = 9</span>

6A + 5B = 7

Subtract and we have 4B = 2

B = 2/4 = 1/2 of an hour

Now put 1/2 back into either equation to solve for A

<span>6A + 5(1/2) = 7
6A + 5/2 = 7
6A = 14/2 -5/2
6A = 9/2
divide by 6 to get A = 9/12 = ¾  hours</span>

<span>Plan A = 3/4 hour</span>

<span> Plan B = 1/2 hour</span>


3 0
3 years ago
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