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Juli2301 [7.4K]
2 years ago
6

Select the correct answer.

Mathematics
1 answer:
Reil [10]2 years ago
6 0

Answer:

$17

Step-by-step explanation:

Multiply 3 and 3 + Multiply 4 and 2

3 x 3 = 9

4 x 2 = 8

Add them up --

Final Result = 9 + 8 = ($)17 in total, for the bouquets that Penny buys--

Hope you understand !

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A trough has ends shaped like isosceles triangles, with width 5 m and height 7 m, and the trough is 12 m long. Water is being pu
Svet_ta [14]

Answer:

\dfrac{dh}{dt}=21 \text{m/min}

the rate of change of height when the water is 1 meter deep is 21 m/min

Step-by-step explanation:

First we need to find the volume of the trough given its dimensions and shape: (it has a prism shape so we can directly use that formula OR we can multiply the area of its triangular face with the length of the trough)

V = \dfrac{1}{2}(bh)\times L

here L is a constant since that won't change as the water is being filled in the trough, however 'b' and 'h' will be changing. The equation has two independent variables and we need to convert this equation so it is only dependent on 'h' (the height of the water).

As its an isosceles triangle we can find a relationship between b and h. the ratio between the b and h will be always be the same:

\dfrac{b}{h} = \dfrac{5}{7}

b=\dfrac{5}{7}h this can be substituted back in the volume equation

V = \dfrac{5}{14}h^2L

the rate of the water flowing in is:

\dfrac{dV}{dt} = 6

The question is asking for the rate of change of height (m/min) hence that can be denoted as: \frac{dh}{dt}

Using the chainrule:

\dfrac{dh}{dt}=\dfrac{dh}{dV}\times \dfrac{dV}{dt}

the only thing missing in this equation is dh/dV which can be easily obtained by differentiating the volume equation with respect to h

V = \dfrac{5}{14}h^2L

\dfrac{dV}{dh} = \dfrac{5}{7}hL

reciprocating

\dfrac{dh}{dV} = \dfrac{7}{5hL}

plugging everything in the chain rule equation:

\dfrac{dh}{dt}=\dfrac{dh}{dV}\times \dfrac{dV}{dt}

\dfrac{dh}{dt}=\dfrac{7}{5hL}\times 6

\dfrac{dh}{dt}=\dfrac{42}{5hL}

L = 12, and h = 1 (when the water is 1m deep)

\dfrac{dh}{dt}=\dfrac{42}{5(1)(12)}

\dfrac{dh}{dt}=21 \text{m/min}

the rate of change of height when the water is 1 meter deep is 21 m/min

6 0
3 years ago
Read 2 more answers
Please solve both of these questions
Alex

Answer:

jane will arrive at 3:41

Mira will arrive at 3:50

so the the difference in time is 9 minutes

—————-

The shaded area = Circle area - square area

circle area = 314

square area = 100

the the shaded area = 214

7 0
3 years ago
What is the value of the expression: 2 - (3x + 5y) if x = -3 and y = 4?
WARRIOR [948]
<h3>Hello there today we will solve your problem</h3>

here is our equation,

2-(3x+5y),

Now we will plug in our numbers

__________________

  1. {\boxed{x=-3}}
  2. {\boxed{y=4}

__________________

2-(3\cdot-3+5\cdot4)

simplify it and we get

2-(-9+20)

2-11

-9

7 0
2 years ago
Read 2 more answers
Four resistors are connected in series such that their total resistance is 50ohm . If the resistance of resistors is 5 ohm , 10o
Katyanochek1 [597]
<h2>Answer:</h2>

\boxed{R_{4}=20\Omega}

<h2>Step-by-step explanation:</h2>

If resistors are in series, so the current  I is the same in all of them. In this problem we have four resistors. So, we can get a relationship between the Equivalent resistance  of series combination and the four resistors as follows:

R_{eq}=R_{1}+R_{2}+R_{3}+R_{4}

R_{eq} is the total resistance 50\Omega. Moreover:

R_{1}=5\Omega \\ R_{2}=10\Omega \\ R_{3}=15\Omega

Therefore:

50=5+10+15+R_{4} \\ \\ R_{4}=50-(5+10+15) \\ \\ R_{4}=50-30 \\ \\ \boxed{R_{4}=20\Omega}

7 0
3 years ago
Hey what's the answer<br><img src="https://tex.z-dn.net/?f=%20-%2011a%283a%20%2B%202a%29" id="TexFormula1" title=" - 11a(3a + 2a
allsm [11]

Answer:

- 11a(3a + 2b) \\  =  - 11 \times 3 \times a \times a + ( - 11 \times 2 \times a \times a) \\  =  - 33 {a}^{2}  - 22ab

<em><u>I </u></em><em><u>hope </u></em><em><u>it </u></em><em><u>helps</u></em>

<em><u>have </u></em><em><u>a </u></em><em><u>great </u></em><em><u>day </u></em>

<em><u>#Liliflim✌️</u></em>

7 0
2 years ago
Read 2 more answers
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