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nevsk [136]
3 years ago
13

Solve this equation

Mathematics
2 answers:
raketka [301]3 years ago
8 0
5^2 would be 25 and it would be 25=3x i think
BARSIC [14]3 years ago
3 0

Answer: x=1/3

Step-by-step explanation:

step-by-step.

3x+1=2

Step 1: Subtract 1 from both sides.

3x+1-1=2-1

3x=1

step 2: Divide both sides by 3 .

3x/3=1/3

x=1/3

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can someone help me out with this?? I am God awful at basic math such as this...apologies if I sound absurdly stupid;;​
GenaCL600 [577]

For graphs, always start with line <em>x</em> then do line <em>y</em>.

4 0
3 years ago
Awarding brainliest!!!
Alex Ar [27]

Answer:

m=3

Step-by-step explanation:

6m+5-3m=7(m-1)

Combine like terms

3m+5=7(m-1)

Distribute the 7

3m+5=7m-7

Subtract 3m from each side

4m-7=5

Add 7 to each side

4m=12

Divide by 4

m=3

8 0
3 years ago
Read 2 more answers
Tracy embroidered 26 quilt blockswith letters and 10 quilt blocks with numbers .She whants her quilt to have 6 rows .How many qu
Julli [10]

26+10=36/6=6

6 blocks in each row.

6 0
3 years ago
Read 2 more answers
Simplest form of 7/10 and 2/10
Juli2301 [7.4K]

Answer:

7/10 can't be simplified, 2/10->1/5

Step-by-step explanation:

7/10 cannot be simplified as 7 and 10 don't have any common factors other than 1

2/10 can be simplified by a factor of 2 to get 1/5

4 0
3 years ago
Read 2 more answers
URGENT!!! 50 POINTS!!! URGENT!!!!!!! Consider the polynomial functions P (x) and Q (x)​ , where neither polynomial is a constant
Nutka1998 [239]

Answer:

Always

Always

Sometimes

Never

Step-by-step explanation:

P(X) + Q(X)

Sum of two polynomials is always a polynomial.

For example, Let P(x) = 3x² and Q(x) = 5x

$ \implies P(x) + Q(x) = 3x² + 5x

This is again a polynomial.

In other words, we can say that Polynomial is closed under addition.

P(x) . Q(x)

Product of two polynomials is again a polynomial.

Let P(x) = 2x and Q(x) = a constant function, 5

Then the product = 10x, is again a polynomial.

Multiplication of two polynomials is closed.

P(x) / Q(x)

This need not always be a polynomial. When Q(x) = a constant function zero, i.e., Q(x) = 0, then the function is not defined.

But let's say P(x) = 5x² and Q(x) = x.

$ \frac{P(x)}{Q(x)} $ = $ \frac{5x^2}{x} $ = 5x, a polynomial.

So, $ \frac{P(x)}{Q(x)} $ is a polynomial sometimes.

We can, say Division is not always closed.

1/Q(x)

This could never be a polynomial. This is not even in the form of a polynomial. So, $ \frac{1}{Q(x)} $ is never a polynomial.

Hence, the answer.

7 0
3 years ago
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