A digit can be 0-9 so one of the factors has to be 8. The other digit is half of 8 which is 4 because if 4 is doubled it equals 8.
<span>The two digits will be 48. So the two products are 6 and 8 because 6 x 8 = 48.</span>
Of three dice, two are labeled normally: 1, 2, 3, 4, 5 , and 6. The third die has sides labeled 2,4,6,8,10, and 12. Two dice are
jolli1 [7]
The ratio of the frequency of a prime rolled using the first two (ordinary)dice to the frequency of a prime rolled using the unusual die and one ordinary die is
<h3>The Cases and there Probable Results</h3>
There are a total of 36 equally probable ways the dice can fall
In the first case, primes are achieved for the following results:
- 2 (one way possible),
- 3 (two ways possible),
- 5 (4 ways possible),
- 7 (six ways possible), and
- 11 (2 ways possible.
So primes are achieved in a total of 15 ways.
In the second case, the prime possibilities are
- 3 (one way possible),
- 5 (two ways),
- 7 (3 ways),
- 11 (3 ways),
- 13 (3 ways), and
- 17 (just one way).
The total is 13 ways.
<h3>How to calculate the ratio of the frequency</h3>
Therefore
How to calculate the ratio of the frequency is Mathematically given as
Frequency ratio is 
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Answer:
(the last one) i think its B
Step-by-step explanation:
Answer: D. 2/3
Step-by-step explanation:
There are 15 markers in total. Out of these 15 markers, there are 5 blue ones.
If Mark reaches into a bag to pull out one marker and hopes it is not blue, there would be a 2/3 probability as 2/3 of the markers are not blue.