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evablogger [386]
3 years ago
9

Can someone please help me?

Mathematics
1 answer:
denis23 [38]3 years ago
4 0
Number 5 is 280 ft because you would just do 20x14
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What is the diameter in the circle above <br>7<br>3.5<br>14<br>3.14​
ira [324]

Answer:

14

Step-by-step explanation:

The diameter is the length from one point on the circle to another, passing through the center. The <em>radius </em>is the length from a point on the circle to its center, so we can always find the diameter by doubling the radius. In this case, with a radius of 7, our diameter is 7 · 2 = 14

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3 years ago
A savings bank invests $58,800 in municipal bonds and earns 12% per year on the investment. How much money is earned per year?
seraphim [82]
To find the answer we simply have to find 12% of 58,800. So to do that, we can multiply it by .12

58,800 • .12 = 7,056

So $7,056 is earned per year
5 0
4 years ago
Read 2 more answers
A kite is flying with its string, which is of length 60 metres, taut.The kite is 20 metres vertically above the ground.a)Find th
chubhunter [2.5K]

a) Due to you have a right triangle, in order to calculate the value of d, use the Pythagorean thorem:

d=\sqrt[]{(60m)^2+(20m)^2}=\sqrt[]{4000m^2}\approx63.2m

Hence, the distance d is approximately 63.2m

b) To find the angle of elevation, use the sine function of θ, as follow:

\begin{gathered} \sin \theta=\frac{opposite}{hypotenuse}=\frac{20m}{60m}=\frac{1}{3} \\ \theta=\sin ^{-1}(\frac{1}{3})\approx19.8 \end{gathered}

Hence, the angle of elevation is approximately 19.8°

5 0
2 years ago
Estimate 1188+405+848 by first rounding each number to the nearest hundred
Fynjy0 [20]

Answer:

about 2300

Step-by-step explanation:

8 0
3 years ago
A researcher has funds to buy enough computing power to number-crunch a problem in 5 years. Computing power per dollar doubles e
amm1812
A) In t months, the number of months required to number-crunch the problem will be
  60*2^(-t/23)
By waiting t months, the researcher has made the total time f(t) to the solution of his problem be
  f(t) = t + 60*2^(-t/23)

The derivative of this is
  f'(t) = 1 + 60*ln(2)*(-1/23)*2^(-t/23)
We want to find the value of t that makes this be zero.
  0 = 1 - 60*ln(2)/23*2^(-t/23)
  2^(-t/23) = 23/(60*ln(2))
  (-t/23)*ln(2) = ln(23/(60*ln(2)))
  t = -23/ln(2)*ln(23/(60*ln(2))) ≈ 19.655

In order to finish his problem as soon as possible, the researcher should wait 19.7 months to buy his computers.


b) For this part of the problem, we want to find the value of "60" that makes t=0 be the solution. Taking the last expression and substituting t=0, 60=c, we get
  0 = -23/ln(2)*ln(23/(c*ln(2)))
  1 = 23/(c*ln(2)) . . . . . taking antilogs
  c = 23/ln(2) ≈ 33.2

The largest value of c for which he should buy the computers immediately is 33.2.

6 0
3 years ago
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