Answer:
72000
Step-by-step explanation:
First five digit number is 10000
And the last five digit number is 99999.
There are 99999-10000+1 five digits in all.
That simplifies to 89999+1=90000.
Any number whose units digit is 5 or 0 is divisble by 5.
10000 is the first five digit number that is divisble by 5.
10000+5k where k is a positive integer can be used to find any after.
The last five digit number divisible by 5 is 99995. What is k then?
10000+5k=99995
5k=89995
k=89995/5
k=17999
How many 5 digit numbers are divisble by 5?
So the first one happens at k=0 and the last one happens at k=17999.
How many numbers is that? 17999+1=18000.
So the number of 5 digit numbers that aren't divisble by 5 is 90000-18000=72000
Answer:
option A.) y-3 = 1/16 (x-2)^2
Step-by-step explanation:
we know that
If the axis of symmetry is parallel to the y-axis, then we have a vertical parabola
The equation of a vertical parabola is equal to
where
(h,k) is the vertex
In this problem we have
(h,k)=(2,3)
p=4
substitute
Answer:
t = 11
Step-by-step explanation:
Before we can solve this word problem, we have to translate first this problem into numerical form. The sum of fifteen and six times a number t is eighty-one can be translated into
15 + 6t = 81
Let's subtract 15 from both sides of the equation .
15 + 6t - 15 = 81 - 15
6t = 66
Divide both sides of the equation by 6.
6t / 6 = 66 / 6
t = 11
