Question

List A contains the numbers [20,10,30], while list B contains the numbers [10,30,20,40,30]. We choose one number from list A randomly and one number from list B randomly. What is the chance that the number we drew from list A is larger than or equal to the number we drew from list B

Answer 1

Chance that the number we drew from list A is larger than or equal to the number we drew from list B is as

Number chosen is 30: $p = \frac{4}{5}$

Number chosen is 10: $p = \frac{1}{5}$

Number chosen is 20:$p = \frac{2}{5}$

Step-by-step explanation:

We have , List A contains the numbers [20,10,30], while list B contains the numbers [10,30,20,40,30]. We choose one number from list A randomly and one number from list B randomly. Let's assume 3 cases for above problem:

Number chosen is 20:

We compare that 20 from list A is greater than or equal to 10 , 20 in list B . So probability that this number drew  from list A is larger than or equal to the number we drew from list B is $p = \frac{2}{5}$.

Number chosen is 10:

We compare that 10 from list A is greater than or equal to 10 in list B . So probability that this number drew  from list A is larger than or equal to the number we drew from list B is $p = \frac{1}{5}$.

Number chosen is 30:

We compare that 30 from list A is greater than or equal to 10 , 20, 30,30 in list B . So probability that this number drew  from list A is larger than or equal to the number we drew from list B is $p = \frac{4}{5}$.

∴ Chance that the number we drew from list A is larger than or equal to the number we drew from list B is as

Number chosen is 30: $p = \frac{4}{5}$

Number chosen is 10: $p = \frac{1}{5}$

Number chosen is 20:$p = \frac{2}{5}$