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4 years ago

What is 23 divded by 4621

Mathematics

2 answers:

DanielleElmas [232]4 years ago

6 0

23/ 4621 is 0.00497728, if you meant 4621/ 23 then it's 200.913043.

IrinaVladis [17]4 years ago

5 0

0.004977277645531 is the correct answer

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a piece of paper has side lengths of 11 inches and 8 inches . what is the perimeter of the piece of paper ?

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Mikey had 104 nickels and 88 dimes she wants to divide the coins into group of each group will have the same number of nickels i

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Step-by-step explanation:

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2 years ago

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The price of products may increase due to inflation and decrease due to depreciation. Marco is studying the change in the price

inn [45]

Answer:

Product A has a greater percentage change in price.

Step-by-step explanation:

Part A:

The price f product A, f (x) after x years is given by:

$f(x) = 0.69\cdot(1.03)^{x}$

After x = 0 years, the price of product A is:

$f(0) = 0.69\cdot(1.03)^{0}=0.69$

After x = 1 years, the price of product A is:

$f(1) = 0.69\cdot(1.03)^{1}=0.69\cdot (1+0.03)=0.69\cdot (1+3\%)$

After 1 year, the price of product A is 3% times more than the original price.

This means that after one year, the new price is 103% of the original price, which means the price product A is increasing by 3%.

Again after x = 2 years, the price of product A is:

$f(2) = 0.69\cdot(1.03)^{2}=[0.69\cdot (1+3\%)]\times (1.03)$

This implies that after 2 years, the price of product A is 103% of the price after year 1.

This implies that the price of product A is 3% more than the previous year.

Thus, the price of product A is increasing each year by 3%.

Part B:

The data for Product B is as follows:

Time (t) Price [f (t)]

1 10,100

2 10,201

3 10,303.01

4 10,406.04

Product B is clearly increasing in price.

Consider the changes in price of Product B in the following intervals of years:

Year 1 - Year 2:

Price in year 1 = $10,100

Price in Year 2 = $10,201

Compute the increase percentage as follows:

$\text{Increase}\%=\frac{10201-10100}{10100}=0.01=1\%$

Year 2 - Year 3:

Price in Year 2 = $10,201

Price in year 3 = $10,303.01

Compute the increase percentage as follows:

$\text{Increase}\%=\frac{10303.01-10201}{10201}=0.01=1\%$

Year 3 - Year 4

Price in year 3 = $10,303.01

Price in Year 4 = $10,406.04

Compute the increase percentage as follows:

$\text{Increase}\%=\frac{10,406.04-10303.01}{10303.01}=0.09999\approx 0.01=1\%$

It is quite clear that the price of product B increases by 1% each year.

Thus, Product A has a greater percentage change in price.

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3 years ago