Answer:
2x²-32 ⇒ x²=16⇒ (-4,4)
4x²-100 ⇒x²=25 ⇒(-5,5)
x²-55=9 ⇒x²=64 ⇒(-8,8)
x²-140=-19 ⇒x²=121 ⇒(-11,11)
2x²-18=0 ⇒x²=9 ⇒(-3,3)
By understanding and applying the characteristics of <em>piecewise</em> functions, the results are listed below:
- r (- 3) = 15
- r (- 1) = 11
- r (1) = - 7
- r (5) = 13
<h3>How to evaluate a piecewise function at given values</h3>
In this question we have a <em>piecewise</em> function formed by three expressions associated with three respective intervals. We need to evaluate the expression at a value of the <em>respective</em> interval:
<h3>r(- 3): </h3>
-3 ∈ (- ∞, -1]
r(- 3) = - 2 · (- 3) + 9
r (- 3) = 15
<h3>r(- 1):</h3>
-1 ∈ (- ∞, -1]
r(- 1) = - 2 · (- 1) + 9
r (- 1) = 11
<h3>r(1):</h3>
1 ∈ (-1, 5)
r(1) = 2 · 1² - 4 · 1 - 5
r (1) = - 7
<h3>r(5):</h3>
5 ∈ [5, + ∞)
r(5) = 4 · 5 - 7
r (5) = 13
By understanding and applying the characteristics of <em>piecewise</em> functions, the results are listed below:
- r (- 3) = 15
- r (- 1) = 11
- r (1) = - 7
- r (5) = 13
To learn more on piecewise functions: brainly.com/question/12561612
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Answer:
the number is 126
Step-by-step explanation:
1) multiply each side by 32: (n-2) / 32 = 4
2) subtract 2 from each side: n-2 = 128
3) n = 126
Answer:
1 A= pi 21^2
2 C=pi 21
3 A= pi 10.5^2
4 C= 2pi 10.5
Step-by-step explanation:
Answer:
The minimum value of this function is -40.
Step-by-step explanation:
Recall that the minimum of a quadratic whose graph is a parabola that opens up, as this one does, is the vertex of the graph. The x-coordinate of the vertex is given by x = -b / (2a), where a is the coefficient of the x^2 term and b is that of the x term.
Here, x = -12 / (2*2), or x = -12/4, or x = -3.
Find the y-value at this x-value: f(-3) = 2(-3)^2 + 12(-3) - 22, or
f(-3) = 2(9) - 36 - 22, or -40.
The vertex is at (-3, -40). The minimum value of this function is -40.
