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Paraphin [41]
3 years ago
12

WhO ElSe Is BoReDdDdD

Mathematics
2 answers:
egoroff_w [7]3 years ago
3 0
STAN TXT AND STREAM IF BORED
mr_godi [17]3 years ago
3 0
Meeeeeeeeeeeeeee!!!!!
You might be interested in
Find the value of x for which x²-3x - 10 /<br>x² + 12x + 36<br>is equal to zero, undefined​
GREYUIT [131]

Answer:

x= -6 twice

Step-by-step explanation:

x^2-3x-10/x^2+12x+36

By using undefined fraction we only take the denominator and equate it to 0

x^2+12x+36=0

x^2+6x+6x+36=0

(x^2+6x)+(6x+36)=0

x(x+6)+6(x+6)=0

(x+6)(x+6)=0

x+6=0 or x+6=0

x= -6 or x= -6

therefore x= -6 twice

6 0
4 years ago
A farmer had large herd of goats. Besides the 4 goats that slept in his bed, he had 7 barns full of goats. How many goats were i
fiasKO [112]
95-4=91 then 91 divided 7=13 (95-4) divided 7=13
6 0
3 years ago
The measures of the angles of a triangle are shown in the figure below. Find the measure of the smallest angle.
nataly862011 [7]

Answer:

(2x+18) degrees

Step-by-step explanation:

A triangle is a total of 180 degrees, so you would do:

(2x+18)+55+(4x+11)=180

(2x+4x)+(18+55+11)=180           <- take out parentheses and add like terms

6x+84=180                         <- subtract 84 from both sides of the equation

6x=96                                    <- divide 6 from each side

x=16

Now that you know what x is you would plug it into each of the angles

Angle 1: 2x+18 --> 2(16)+18= 32+18= 50

Angle 2: 55

Angle 3: 4x+11 --> 4(16)+18= 64+18= 82

Then out of these three angles of the triangle, angle 1 (2x+18) would be the smallest.

4 0
3 years ago
Read 2 more answers
Let p = the product of all the odd integers between 500 and 598, and let q = the product of all the odd integers between 500 and
tia_tia [17]

p=501\cdot503\cdot\cdots\cdot597

q=\underbrace{501\cdot503\cdot\cdots\cdot597}_p\cdot599\cdot601

So we have q=359,999p. Then

\dfrac1p+\dfrac1q=\dfrac{359,999}{359,999p}+\dfrac1q=\dfrac{359,999+1}q=\dfrac{360,000}q

and the answer is D.

4 0
3 years ago
A library building is in the shape of a rectangle. Its floor has a length of (3x + 5) meters and a width of (5x − 1) meters. The
malfutka [58]
We can use the Front Outside Inside Last (FOIL) method to expand the double bracket

(3x+5)(5x-1)

Front ⇒(3x)(5x)=15 x^{2}
Outside ⇒(3x)(-1)=-3x
Inside ⇒(5)(5x)=25x
Last ⇒(5)(-1)=-5

Put the four terms together we have
15 x^{2} -3x+25x-5, then collect like terms
15 x^{2} +22x-5
5 0
3 years ago
Read 2 more answers
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