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Paraphin [41]
3 years ago
12

WhO ElSe Is BoReDdDdD

Mathematics
2 answers:
egoroff_w [7]3 years ago
3 0
STAN TXT AND STREAM IF BORED
mr_godi [17]3 years ago
3 0
Meeeeeeeeeeeeeee!!!!!
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What are the missing letters in the pattern? kr, np, _____ , tl , wj, ...
maria [59]
Your answer is , qn.
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3 years ago
What happens to the standard deviation of the average of a sample as the sample size increases? Group of answer choices It gets
NeX [460]

Answer:

Gets smaller

Step-by-step explanation:

- The standard deviation is the quantification of spread of data. According to descriptive statistics the standard deviation s is given by:

                             s = Σ (  x - u ) / sqrt ( n )

Where, n : sample size

            u : Mean value

- So we see that standard deviation (s) is inversely proportional to square root of sample size (n).

- We can see that as sample size (n) increases the standard deviation (s) decreases.

3 0
3 years ago
What is the slop of 2x+3y-9=0
MAVERICK [17]

Answer:

Step-by-step explanation:

We need to write this equation in y=mx+b where m is the slope.

3y= -2x +9

y= -2/3 +9

So now that it is in the form of y=mx+b, we can find the slope. -2/3 is the slope of the equation. Hope that helps!

3 0
3 years ago
WHAT IS THE ANSWER PLEASE
viva [34]

Answer:

.top the at is 71 ebecaus  because one third the IsIs

Step-by-step explanation:

6 0
3 years ago
From a large number of actuarial exam scores, a random sample of scores is selected, and it is found that of these are passing s
Mnenie [13.5K]

<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

  • The lower limit is 0.5.
  • The upper limit is 0.7.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of \frac{1+\alpha}{2}.

60 out of 100 scores are passing scores, hence n = 100, \pi = \frac{60}{100} = 0.6

95% confidence level

So \alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 - 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.5

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 + 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.7

The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

  • The lower limit is 0.5.
  • The upper limit is 0.7.

A similar problem is given at brainly.com/question/16807970

5 0
3 years ago
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