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scoundrel [369]
3 years ago
5

1/3 x = 1/6 write answer as a fraction

Mathematics
2 answers:
Andrews [41]3 years ago
6 0

Step-by-step explanation:

1/3x=1/6

x/3=1/6

cross multiply

6x=3

divide both sides by 6

x=3/6

x=1/2

andrey2020 [161]3 years ago
6 0

Answer:

\frac{1}{2} = x

Step-by-step explanation:

\frac{1}{6} = \frac{1}{3}x \\ \\ \frac{\frac{1}{6}}{\frac{1}{3}} = \frac{1}{2} \\ \\ \frac{1}{2} = x

I am joyous to assist you anytime.

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Use the diagram to answer, given that line LM is a common tangent to circle P and circle Q. Leave answers in simplified radical
drek231 [11]

Answer:

PL = 9

PN = 5√5

Step-by-step explanation:

8/12 = 6/PL

8PL = 72

PL = 9

PN² = 10² + 5² = 100 + 25 = 125

PN = √125 = 5√5

7 0
3 years ago
Simplify<br> 7xy^2z^3- 4xy^2z^3+2x^2yz^2-3xy^2z^3
aksik [14]

Answer:

(Hope this helps can I pls have brainlist (crown)☺️)

Step-by-step explanation:

In pic

(Credits:Symbolab)

3 0
3 years ago
What is the sum of a-1/abc^3 + 3-b/abc^3
Lyrx [107]
The answer is\frac{a-b+2}{abc^{3} }

The expression is \frac{a-1}{abc^{3} } + \frac{3-b}{abc^{3} }

Since \frac{a}{x} + \frac{b}{x} = \frac{a+b}{x}, then:

\frac{a-1}{abc^{3} } + \frac{3-b}{abc^{3} } = \frac{a-1+3-b}{abc^{3} }= \frac{a-b-1+3}{abc^{3} }=\frac{a-b+2}{abc^{3} }
4 0
3 years ago
Can someone help me with this
mash [69]

The center of the circle is (h,k) = (-2,-3)

The radius of the circle is r = 2

The standard form of equation of the circle is

{(x + 2)}^{2}  +  {(y + 3)}^{2}  = 4

<h3>How to find the center, radius and standrad form of the circle?</h3>

The general form of equation of the circle is

{(x - h)}^{2}  +  {(y - k)}^{2}  =  {r}^{2}

Here, (h,k) means centre of the circle.

r means radius of the circle.

given that coordinate points of centre of circle is (-2,-3).

Hence the (h,k) = (-2,-3)

<h3>How to find the radius of the circle?</h3>

Now to find the radius of the circle

The distance from a circle's centre to its circumference is its radius.

The distance from a circle's centre (-2,-3) to its circumference (0,-3) is its radius.

using the formula, distance between the two points to obtain radius.

d =  \sqrt{(x1 - x2) {}^{2}  +  {(y1 - y2)}^{2} }  \\ r =  \sqrt{ {( - 2 - 0)}^{2} +  {( - 3 - ( - 3))}^{2}  }  \\ r =  \sqrt{ {( - 2)}^{2} +  {( - 3 + 3)}^{2}  }  \\ r =  \sqrt{ {4}^{2} + 0 }  \\ r =  \sqrt{4}  \\ r = 2

<h3>How to find the standard form of equation of the circle?</h3>

(h,k) = (-2,-3)

r = 2

subtitue the (h,k) and r values to get the standard form of equation of the circle.

(x - h) {}^{2}  +  {(y - k)}^{2}  =  {r}^{2}

{(x - ( - 2))}^{2}  +  {(y - ( - 3))}^{2} =  {r}^{2}

{(x + 2)}^{2}  +  {(y + 3)}^{2}  = 4

Learn more about circle, refer:

brainly.com/question/24810873

#SPJ9

5 0
2 years ago
I need help with this.. Anybodyyy??!
Marta_Voda [28]

Step-by-step explanation:

Given

c² = a² + b²

Making a² subject then

a² = c² - b²

Hope it will help :)

4 0
3 years ago
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