2 years ago

Enforce is to impose as fued is to

Mathematics

1 answer:

jenyasd209 [6]2 years ago

8 0

The reasonable answer should be Dispute.

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Which expression can be used to find 52% of 230?

pogonyaev

Hello,

52% of 230 = 52/100 × 230 = 0,52 × 230 = 119,6

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1 year ago

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How many times greater is the value of 3 in 300 than the value of the 3 in 30

Vikki [24]

Well it sounds like you mean smaller, not greater. 3/300 = 1/100 while 3/30 = 1/10. So 3 out of 300 is 10 times SMALLER than 3 out of 30.

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Write the sentence as an equation. 396 subtracted from p is t

Paladinen [302]

P - 396 = t <== ur equation

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babunello [35]

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Express the function as the sum of a power series by first using partial fractions. f(x) = 8 x2 − 4x − 12 f(x) = ∞ n = 0 find th

alexandr1967 [171]

I'm guessing the function is

$f(x)=\dfrac8{x^2-4x-12}=\dfrac8{(x-6)(x+2)}$

which, split into partial fractions, is equivalent to

$\dfrac1{x-6}-\dfrac1{x+2}$

Recall that for $|x|$ we have

$\dfrac1{1-x}=\displaystyle\sum_{n=0}^\infty x^n$

With some rearranging, we find

$\dfrac1{x-6}=-\dfrac16\dfrac1{1-\frac x6}=\displaystyle-\frac16\sum_{n=0}^\infty\left(\frac x6\right)^n$

valid for $\left|\dfrac x6\right|$ , or $|x|$ , and

$\dfrac1{x+2}=\dfrac12\dfrac1{1-\left(-\frac x2\right)}=\displaystyle\frac12\sum_{n=0}^\infty\left(-\frac x2\right)^n$

valid for $\left|-\dfrac x2\right|$ , or $|x|$ .

So we have

$f(x)=\displaystyle-\frac16\sum_{n=0}^\infty\left(\frac x6\right)^n-\frac12\sum_{n=0}^\infty\left(-\frac x2\right)^n$

$f(x)=\displaystyle-\sum_{n=0}^\infty\left(\frac{x^n}{6^{n+1}}+\frac{(-x)^n}{2^{n+1}}\right)$

$f(x)=\displaystyle-\sum_{n=0}^\infty\frac{1+3(-3)^n}{6^{n+1}}x^n$

Taken together, the power series for $f(x)$ can only converge for $|x|$ , or $-2$ .

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2 years ago