<span>Lets say the 1st die rolled a 2 -
there would be 2 combinations for which the sum of dice being < 5 :
2,1
2,2
Now say the 2nd die rolled a 2 -
there would be 2 combinations for which the sum of dice being < 5 :
1,2
2,2
Now we want to count all cases where either dice showed a 2 and sum of the dice was < 5. However note above that the roll (2,2) is counted twice.
So there are three unique dice roll combinations which answer the criteria of at least one die showing 2, and sum of dice < 5:
1,2
2,1
2,2
The total number of unique outcomes for two dice is 6*6=36 .
So, the probability you are looking for is 3/36 = 1/12</span>
The answer is 51 first u multiply and divide then calculate
Answer:
The height of the right trapezoid is 
Step-by-step explanation:
Let
x ----> the height of the right trapezoid in units
we know that
The perimeter of the figure is equal to
we have
---> because is a square
substitute
-----> equation A
<em>In the right triangle CDH</em>
so
Remember that 
so
substitute the values in the equation A
-----> equation A
![6=x[5+\sqrt{3}]](https://tex.z-dn.net/?f=6%3Dx%5B5%2B%5Csqrt%7B3%7D%5D)
Answer:
z=12
Step-by-step explanation:
z+15=27
move constant
z=27-15
z=12
